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frutty [35]
2 years ago
13

Bill has x pence.

Mathematics
1 answer:
Anna [14]2 years ago
3 0
Ben has x pence, but Bill has 2x (twice more)
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Decide which title best describes all of the expressions in each column of the table. Place the correct title at the top of each
irga5000 [103]
For the first one is has greater then 3 terms
The middle one is has exactly one term
And the last one is has two terms
I believe I hope this helps
4 0
3 years ago
A small company 's net income for the first 6 months of the year was 76.500 and for the last six months it was 100,000 . What is
inna [77]

Answer:The ratio of net income in the first 6 months, to the last six months is $76,500 / $100,000. This simplifies intuitively as follows:

76500/100000

Dividing by 100: 765/1000

Dividing by 5: 153/200

The denominator 200 is only divisible by the prime numbers 2 and 5, and since the numerator 153 is not divisible by either 2 or 5, this means that this is in simplest form, and the final answer is 153/200.

Step-by-step explanation:i did the research for you this isnt my own answer therefore don't give me the credit. but hope this helped you tho :D

5 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
astra-53 [7]

Answer:

3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow  y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}

Step-by-step explanation:

The period of the functions y=a\cos(bx+c) , y=a\sin(bx+c), y=a\sec (bx+c) or y=a\csc(bx+c) can be calculated as

T=\dfrac{2\pi}{b}

The period of the functions y=a\tan(bx+c) or y=a\cot(bx+c) can be calculated as

T=\dfrac{\pi}{b}

A. The period of the function y=-3\tan 3x is

T=\dfrac{\pi}{3}

B. The period of the function y=6\sin 3x is

T=\dfrac{2\pi}{3}

C. The period of the function y=-4\cot \dfrac{x}{4} is

T=\dfrac{\pi}{\frac{1}{4}}=4\pi

D. The period of the function y=2\cos \dfrac{2x}{3} is

T=\dfrac{2\pi}{\frac{2}{3}}=3\pi

E. The period of the function y=-\dfrac{2}{3}\sec \dfrac{x}{5} is

T=\dfrac{2\pi}{\frac{1}{5}}=10\pi

5 0
4 years ago
(Please help ill give brainliest)
elena-s [515]

Answer:

80 answer is 80

Step-by-step explanation:

50+30 = 80 answer

6 0
2 years ago
Gerry thinks that the points (4,2) and (−1,4) form a line perpendicular to a line with slope 4. Do you agree? Why
faust18 [17]

Answer:

The answer to your question is these lines are not perpendicular.

Step-by-step explanation:

Data

A (4, 2)

B (-1, 4)

slope = m = 4

Perpendicular lines mean that these lines cross and form an angle of 90°. Also, the slope of perpendicular lines is negative reciprocals.

Process

1.- Find the slope of the second line and compare it to the slope given.

slope = \frac{y2 - y1}{x2 - x1}

Substitution

slope = \frac{4 - 2}{-1 - 4}

Simplification and result

slope = \frac{-2}{5}

-2/5 is not a negative reciprocal of 4, so these lines are not perpendicular.

4 0
4 years ago
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