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2 years ago

Bill has x pence.

Mathematics

1 answer:

Anna [14]2 years ago

3 0

Ben has x pence, but Bill has 2x (twice more)

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Is 2 the solution to x to the third minus x minus 6 equals 0

Natali [406]

X actually equals the cube root of 6
${x}^{3} - 6 = 0 \\ {x}^{3} = 6 \\ x = \sqrt[3]{6}$

5 0

3 years ago

Checking account a has a service fee of $3 and a per check fee of $0.02 while checking account b charges a monthly fee of $2

Alecsey [184]

Idk how to answer this

6 0

3 years ago

Read 2 more answers

After every eighth visit to a restaurant you receive a free beverage. After every tenth visit you receive a free appetizer. If y

Kaylis [27]

Answer:

40th and 80th visit

the first visit where you receive both is the 40th

Step-by-step explanation:

personally, I believe that the simplest way to solve this is use an excel spreadsheet to see which visits would include both a free beverage and a free appetizer:

both rewards would happen only twice, at the 40th and 80th visit.

you can also calculate it mathematically since multiples of 8 and 10 do not repeat themselves very much, only when 8 is multiplied by 5 and 10.

4 0

3 years ago

Read 2 more answers

At the market, 2.4 pounds of carrots cost $1.68 and 1.8 pounds of broccoli cost $1.53. How much more does 1 pound of broccoli co

Greeley [361]

For calculating that, you have to find the unit rate first;

2.4 pound carrot = $1.68

1 pound carrot = $1.68/2.4 = $0.7

1.8 pound broccoli = $1.53

1 pound broccoli = $1.53/1.8 = $0.85

So, it would be = $0.85 - $0.7 = $0.15

SO, YOUR ANSWER IS $0.15

5 0

3 years ago

The rectangle below has an area of 6n^4+20n^3+14n^26n 4 +20n 3 +14n 2 6, n, start superscript, 4, end superscript, plus, 20, n,

Sindrei [870]

Given:

Area of rectangle = $6n^4+20n^3+14n^2$

Width of the rectangle is equal to the greatest common monomial factor of $6n^4, 20n^3,14n^2$ .

To find:

Length and width of the rectangle.

Solution:

Width of the rectangle is equal to the greatest common monomial factor of $6n^4, 20n^3,14n^2$ is

$6n^4=2\times 3\times n\times n\times n\times n$

$20n^3=2\times 2\times 5\times n\times n\times n$

$14n^2=2\times 7\times n\times n$

Now,

$GCF(6n^4, 20n^3,14n^2)=2\times n\times n=2n^2$

So, width of the rectangle is $2n^2$ .

Area of rectangle is

$Area=6n^4+20n^3+14n^2$

Taking out GCF, we get

$Area=2n^2(3n^2+10n+7)$

We know that, area of a rectangle is the product of its length and width.

Since, width of the rectangle is $2n^2$ , therefore length of the rectangle is $(3n^2+10n+7)$ .

5 0

3 years ago