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Andreas93 [3]
2 years ago
5

Evaluate the expression and enter the answer as a fraction in lowest terms, using the slash (/) for the fraction bar.

Mathematics
1 answer:
Naya [18.7K]2 years ago
8 0

Answer:

5/21

Step-by-step explanation:

Change division sign to multiplication and flip second fraction upside down

1/3 x 5/7 =  5/21

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What is the range of y = (x - 5)^2 – 1?
Setler79 [48]

1.  The graph is a parabola.

2. The parabola opens up, because there's no negative number in front of (x-5)^2.

3. The vertext is (5,-1), because of the vertex form.

This means that that -1 will be the least y-value used on the graph and the garph will open up from there.

The range is (-1, infinity) or { y | y > -1 }.

8 0
3 years ago
The length and width of a rectangle are measured as 55 cm and 49 cm, respectively, with an error in measurement of at most 0.1 c
valentina_108 [34]

Answer:

The maximum error in the calculated area of the rectangle is 10.4 \:cm^2

Step-by-step explanation:

The area of a rectangle with length L and width W is A= L\cdot W so the differential of <em>A</em> is

dA=\frac{\partial A}{\partial L} \Delta L+\frac{\partial A}{\partial W} \Delta W

\frac{\partial A}{\partial L} = W\\\frac{\partial A}{\partial W}=L so

dA=W\Delta L+L \Delta W

We know that each error is at most 0.1 cm, we have |\Delta L|\leq 0.1, |\Delta W|\leq 0.1. To find the maximum error in the calculated area of the rectangle we take \Delta L = 0.1, \Delta W = 0.1 and L=55, W=49. This gives

dA=49\cdot 0.1+55 \cdot 0.1

dA=10.4

Thus the maximum error in the calculated area of the rectangle is 10.4 \:cm^2

4 0
3 years ago
A plumber charges 130 to start job plus 56 per hour . How many hours did she work if the total bill is 214
iragen [17]

Answer:

The plumber worked for 1.5 hours

Step-by-step explanation:

y = 130 + 56x

Substitute 214 for y in the equation

214 = 130 + 56x

-130   -130                      Subtract 130 from both sides

84 = 56x                         Divide both sides by 56

1.5 = x

4 0
3 years ago
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it is 5

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Is there a picture along with the question
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