Evaluate the expression and enter the answer as a fraction in lowest terms, using the slash (/) for the fraction bar.
1 answer:
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Answer:
The draining time when only the big drain is opened is 2.303 hours.
The draining time when only the small drain is opened is 5.303 hours.
Step-by-step explanation:
From Physics, we know that volume flow rate (), measured in liters per hour, is directly proportional to draining time (
), measured in hours. That is:
(Eq. 1)
Where is the proportionality constant, measured in liters.
From statement, we have the following three expressions:
(i) <em>Large and small drains are opened</em>
(Eq. 2)
(ii) <em>Only the small drain is opened</em>
(Eq. 3)
(iii) <em>Only the big drain is opened</em>
(Eq. 4)
By applying (Eqs. 3, 4) in (Eq. 2) and making some algebraic handling, we find that:
(Eq. 5)
Whose roots are determined by the Quadratic Formula:
and
Only the first roots offers a solution that is physically reasonable. Hence, the draining time when only the big drain is opened is 2.303 hours. And the time needed for the small drain is calculated by the following formula:
The draining time when only the small drain is opened is 5.303 hours.
The coordinates of B' are 3 and -12. so option D is correct (3, -12)
<h3>How to find the coordinates of B'?</h3>The point P(x, y) may undergo translation to form P' by using a defined translation rule :
If given the rule T(a, b) synch that P undergoes translation on T; then we will have P'(x+a; y+b)
Therefore,
The point B has its coordinates as B(1, - 5)
Translation rule, T(2, - 7) then the coordination of B after undergoing transformation according to T2;
B(1, - 5) - - - > T(2, - 7) - - - - > B'(1+2 ; - 5+-7)
= B'(3, -12)
Hence, the coordinates of B' are 3 and -12. so option D is correct.
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