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LenaWriter [7]
1 year ago
13

Write a python program to change variable value of your previous result percentage to your current percentage of mid-term

Computers and Technology
1 answer:
Sauron [17]1 year ago
3 0

Answer: Make one variable equal to the current percentage and do <em>mid term = current percentage</em>. Then when to put in the current percentage it will always change the midterm score.

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At the time of building system ,there is the requirement of many resources for the development.There is the requirement of the software skills, programming knowledge, resources and tools for the working and designing.Thus, there are different resources, people,skills processes, problem solving skill etc required for the building of the system.

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A(n) ____________ specifies a variable's name and data type.
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What has global css rulesets of an angular 8 project mcq.
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7 0
2 years ago
Write the following function without using the C++ string class or any functions in the standard library, including strlen(). Yo
dolphi86 [110]

Answer:

The function in C++ is as follows

int chkInd(string str1, string str2){    

int lenstr1=0;

while(str1[lenstr1] != '\0'){  lenstr1++;  }

int index = 0; int retIndex=0;

for(int i=lenstr1-1;i>=0; i--){

   while (str2[index] != '\0'){

       if (str1[i] == str2[index]){

           retIndex=1;

           break;         }

       else{   retIndex=0;      }

  index++;    }

  if (retIndex == 0){   return i;   }else{return -1;}}

}

Explanation:

This defines the function

int chkInd(string str1, string str2){    

First, the length of str1 is initialized to 0

int lenstr1=0;

The following loop then calculates the length of str1

while(str1[lenstr1] != '\0'){  lenstr1++;  }

This initializes the current index and the returned index to 0

int index = 0; int retIndex=0;

This iterates through str1

for(int i=lenstr1-1;i>=0; i--){

This loop is repeated while there are characters in str2

   while (str2[index] != '\0'){

If current element of str2 and str1 are the same

       if (str1[i] == str2[index]){

Set the returned index to 1

           retIndex=1;

Then exit the loop

           break;         }

If otherwise, set the returned index to 0

       else{   retIndex=0;      }

Increase index by 1

  index++;    }

This returns the calculated returned index; if no matching is found, it returns -1

  if (retIndex == 0){   return i;   }else{return -1;}}

}

4 0
3 years ago
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