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Soloha48 [4]
2 years ago
11

Select the correct answer.

Computers and Technology
1 answer:
Ierofanga [76]2 years ago
5 0

The program which would help Eva convert a Lisp file into machine code by interpreting only a single line of code at a time is: A.  interpreters

Interpreters can be defined as computer software programs that are designed to translate (interpret) a programming language (code) into machine code, especially by interpreting only a single line of code at a time.

Hence, an interpreter executes the instructions that are written in a programming language (code) one after the other (instruction by instruction), before it translate (interpret) the next line of code.

On the other hand, a compiler takes the entire program (code) and interprets them.

In conclusion, an interpreter can help Eva convert a Lisp file into machine code by interpreting only a single line of code at a time.

Rea d more: brainly.com/question/21130620

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Consider a company that needs to sort an array of structures of type Customer by balance, with the largest balance first. Here i
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Answer:

#include <iostream>

#include <string>

#include <cstring>

#include <cstdlib>

using namespace std;

struct Person

{

string name;

int age;

};

int main()

{

struct Person data[10];

struct Person *pData[10],*temp;

string names[] = {"a","b","c","g","z","l","p","q","r","w"};

int num[] = {4,6,34,8,13,90,33,22,18,23};

for(int i=0;i<9;i++)

{

data[i].name = names[i];

data[i].age = num[i];

pData[i] = &data[i];

}

for(int i=0;i<9;i++)

{

for(int j=i+1;j<9;j++)

{

if(pData[i]->name.compare(pData[j]->name)>0)

{

temp = pData[i];

pData[i] = pData[j];

pData[j] = temp;

}

}

}

for(int i=0;i<9;i++)

{

cout<<pData[i]->name<<" "<<pData[i]->age<<endl;

}

}

Explanation:

The line #include <iostream> initializes the program.

This program created an array of only 10 structures, Customer data. Also defined an auxiliary array Customer *pData.

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