Answer:
arithmetic progression problem
<span>The vertices of are D(7, 3), E(4, -3), and F(10, -3)
Prove tat DE = DF
Length of a segment = </span>√[(x₂ - x₁) +(y₂ -y₁)]
DE = √([4-7)² + (-3 -3)²] = √45 = 3√5
DF = √[(10-7)² +(-3 -3)²] = √45 b= 3√5
Hence DE = DF = 3√5 and DEF is ISOSCELES
Step-by-step explanation:
10. a1=3, a2=1, a3=3, a4=1, a5=3
11. a3=2x1=2, a4=2x2=4, a5=4x2=8
hope that helps :)
Answer:
B = 48.7°, C = 61.3°, b = 12.0
Step-by-step explanation:
A triangle solver makes short work of this. (See below.)
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If you're interested in solving this using only calculator trig functions (and not the solver function), you can use the Law of Sines:
sin(C)/c = sin(A)/a
sin(C) = (c/a)sin(A)
C = arcsin(c/a·sin(A)) = arcsin(14/15·sin(70°))
C ≈ 61.3°
From the sum of angles, the third angle is ...
B = 180° -A -C = 180° -70° -61.3°
B = 48.7°
Again from the Law of Sines:
b/sin(B) = a/sin(A)
b = a·sin(B)/sin(A) = 15·sin(48.7°)/sin(70°)
b ≈ 12.0