All categories

3 years ago

A scale on a drawing is 0.5 mm : 4 cm. the height of the drawing is 4.5 millimeters. what is the actual height of the object?

Mathematics

2 answers:

hoa [83]3 years ago

5 0

4.5 * 4 / 0.5 = 36 cm

garri49 [273]3 years ago

5 0

So this is what you do,
4.5 divided by .5 and that = 9
then you do 9x4 and you get 36
so your answer would be... 36 cm.

You might be interested in

What is the measure of XYZ?

ASHA 777 [7]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Write the congruency statement for the triangles. _______In triangles MNO and JKL, there are two congruent sides and included an

mafiozo [28]

Answer:

ΔJKL ≅ ΔMNO by SAS

Step-by-step explanation:

The question is incomplete, the question is as following:

ΔMNO is shown.

Which Δ below can be shown to be congruent to ΔMNO with only the given information?

Name the postulate that justifies your answer (SAS, AAS, HL, ASA or SSS).

Write the congruency statement for the triangles.

And see the attached figure which represent ΔMNO

==========================================================

Check the given options to see which triangle from the option will be congruent to ΔMNO

1. In triangles MNO and ABC, there are two congruent sides and non-included angle - which mean (angle - side - side)

The (angle - side - side) Postulate does not exist because an angle and two sides does not guarantee that two triangles are congruent.

2. In triangles MNO and DEF, there are two congruent sides - there is not enough information

3. In triangles MNO and GHI, there are three congruent angles - which mean AAA (angle - angle - angle)

The AAA Postulate does not exist because an angle and two sides does not guarantee that two triangles are congruent. This postulate is used to prove the similarity between the triangles.

4. In triangles MNO and JKL, there are two congruent sides and included angle - SAS (side - angle - side)

MN ≅ JK , MO ≅ JL , ∠M ≅ ∠J

5 0

3 years ago

What is the probability you roll doubles on two 6 sides dice please show work

Mars2501 [29]

Answer:

1/6

Step-by-step explanation:

We can start by determining all the different combinations we can get.

We are using 6 sided dices, so we have a chance of getting 6 different numbers for each dice.

If we only have 1 dice, the our possible values would be:

1, 2, 3, 4, 5, 6

However, we have 2 dices. As such, our combinations have been multiplied, and now our possibilities are:

(1 , 1) , (1 , 2) , (1 , 3) , (1 , 4) , (1 , 5) , (1 , 6) , (2 , 1) , (2 , 2) , (2 , 3) , (2 , 4) , (2 , 5) , (2 ,6), and so on for 3, 4, 5, and 6

We can find the number of combinations by simply multiplying the amount of possible values for each dice.

Since both dices have 6 possible values, we multiply 6 by 6, and the amount of possible combinations is 36.

Now, let's determine the possibility for getting a double.

First, let's determine how many doubles we can get:

(1 , 1) , (2 , 2) , (3 , 3) , (4 , 4) , (5 , 5) , (6 ,6)

There are 6 different combinations for rolling a double.

So, our probability of rolling a double on two 6 sided dices is 6 out of 36

We can simplify that to 1 out of 6.

So the probability of rolling a double on two 6 sided dices is 1/6

8 0

3 years ago

Solve pls, ans should be 0, add working

Bond [772]

Step-by-step explanation:

Given: {x+(1/x)}³ = 3

Asked: x³ + (1/x³) = ?

Solution:

Method 1:

We have, {x+(1/x)}³ = 3

Comparing the expression with (a+b)³, we get

a = x

b = (1/x)

Using identity (a+b)³ = a³+b³+3ab(a+b), we get

⇛{x+(1/x)}³ = 3

⇛(x)³ + (1/x)³ + 3(x)(1/x){x + (1/x)} = 3

⇛(x*x*x) + (1*1*1/3*3*3) + 3(x)(1/x){x + (1/x)} = 3

⇛x³ + (1/x³) + 3(x)(1/x){x + (1/x)} = 3

⇛x³ + (1/x³) + 3{x + (1/x)} = 3

⇛x³ + (1/x³) + 3(x) + 3(1/x) = 3

⇛x³ + (1/x³) + 3x + (3/x) = 3

Our answer came incorrect.

Let's try..

Method 2:

We have,

[x+(1/x)]³ = 3

On taking cube root both sides then

⇛³√[{ x+(1/x)}³ ] = ³√3

⇛x+(1/x) = ³√3 -----(1)

We know that

a³+b³ = (a+b)³-3ab(a+b)

⇛x³+(1/x)³ = [x+(1/x)]³ - 3(x)(1/x)[x+(1/x)]

⇛x³+(1/x³) = (3)-3(1)(³√3)

[since, {x + (1/x)} = ³√3 from equation (1)]

⇛x³+(1/x)³ = 3-3 ×³√3

⇛x³ + (1/x³) = 3- ³√81 (or )

⇛x³ + (1/x³) = 3(1-³√3)

Therefore, x³ + (1/x³) = 3(1 - cube root of 3)

It is impossible to get zero

6 0

3 years ago

Can you simplify 3k+8-k+72

Lelu [443]

Answer:

2k + 80

Step-by-step explanation:

Combine like terms.

3k + 8 - k + 72 =

= 3k - k + 8 + 72

= 2k + 80

4 0

3 years ago

Read 2 more answers