Answer:
Outliers have great effect on the mean and standard deviation of the data set
Step-by-step explanation:
Mean =(43+37+50+51+58+52+45+45+58+130)/10
Mean= 579/10
Mean = 57.9
Arranging in ascending order
= 37,43,45,45,50,51,52,58,58,130
Median= (50+51)/2
Median= 101/2
Median= 50.5
IQR= (130-37)/2
IQR= 93/2
IQR= 46.5
Standard deviation
=√(((37-57.9)²+(43-57.9)²+(45-57.9)²+(45-57.9)²+(50-57.9)²+(51-57.9)²+(52-57.9)²+(58-57.9)²+(58-57.9)²+(130-57.9)²)/10)
Standard deviation= 25.1
1.5*(46.5)= 69.75
The number more than 69.75 is 130 and it's the outlier
Without outlier
Mean= (43+37+50+51+58+52+45+45+58)/9
Mean = 449/9
Mean = 49.88
Arranging in ascending order
= 37,43,45,45,50,51,52,58,58
Median= 50
IQR= (58-37)/2
IQR=21/2
IQR=10.5
Standard deviation
