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Blababa [14]
2 years ago
8

Complete the sentence. Forty-five percent of 120 is .

Mathematics
2 answers:
Law Incorporation [45]2 years ago
7 0

Answer:

54

Step-by-step explanation:

45% * 120 = 54

charle [14.2K]2 years ago
5 0
The answer is 54 120•45/100=54
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Write the equation in slope-intercept form of a line that has a slope of 1/3 and passes through the point (-6, 0).
Vesna [10]

Answer: y = 1/3x +2

Step-by-step explanation:

The equation of line in slope - point form is given as:

y - y_{1} = m ( x - x_{1} )

m = 1/3

y_{1} = 0

x_{1} = -6

substituting into the formula , we have

y - 0 = 1/3 ( x - {-6} )

y = 1/3 (x+6)

y = 1/3x +2

5 0
3 years ago
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The bar graph below shows the attendance at school dances. The ticket per price for each dance is $5 per student. Which two danc
topjm [15]

It's B because all the students that attended added together is 320 and 37.5 of 320 is 120

6 0
3 years ago
Point m lies between points l and n on line segment l n . the space between l and m is 10 x 8. the space between m and n is 5 x
Ivenika [448]

The length of line segment l n on which point m lines in between is 64 units. Option 4 is the correct option.

<h3>What is the length of line segment?</h3>

Length of a line segment is the distance of both the ends of it.

Point m lies between points l and n on line segment l n .

  • The space between l and m is 10x 8.
  • The space between m and n is 5x -4.

The value of line segment LN is,

LN = 12x +16

The sum of LM and LN is equal to the line segment LN. Thus,

LM+MN=LN\\10x +8+(5x-4)=12x+ 16\\10x +8+5x-4=12x+ 16\\10x+5x-12x=16 -8+4\\3x=12\\x=\dfrac{12}{3}\\x=4

Put this value of x in the equation of line segment LN,

LN = 12(4) +16\\LN=48+16\\LN=64\rm\; units

Thus, the length of line segment l n on which point m lines in between is 64 units. Option 4 is the correct option.

Learn more about the line segment here;

brainly.com/question/2437195

7 0
2 years ago
Solve the Differential equation (x^2 + y^2) dx + (x^2 - xy) dy = 0
natita [175]

Answer:

\frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C

Step-by-step explanation:

Given differential equation,

(x^2 + y^2) dx + (x^2 - xy) dy = 0

\implies \frac{dy}{dx}=-\frac{x^2 + y^2}{x^2 - xy}----(1)

Let y = vx

Differentiating with respect to x,

\frac{dy}{dx}=v+x\frac{dv}{dx}

From equation (1),

v+x\frac{dv}{dx}=-\frac{x^2 + (vx)^2}{x^2 - x(vx)}

v+x\frac{dv}{dx}=-\frac{x^2 + v^2x^2}{x^2 - vx^2}

v+x\frac{dv}{dx}=-\frac{1 + v^2}{1 - v}

v+x\frac{dv}{dx}=\frac{1 + v^2}{v-1}

x\frac{dv}{dx}=\frac{1 + v^2}{v-1}-v

x\frac{dv}{dx}=\frac{1 + v^2-v^2+v}{v-1}

x\frac{dv}{dx}=\frac{v+1}{v-1}

\frac{v-1}{v+1}dv=\frac{1}{x}dx

Integrating both sides,

\int{\frac{v-1}{v+1}}dv=\int{\frac{1}{x}}dx

\int{\frac{v-1+1-1}{v+1}}dv=lnx + C

\int{1-\frac{2}{v+1}}dv=lnx + C

v-2ln(v+1)=lnx+C

Now, y = vx ⇒ v = y/x

\implies \frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C

5 0
3 years ago
Find the area of a sector with an arc length of 60 in. and a radius of 15 in.
Sonbull [250]

Answer:

C. 450 in.2

Step-by-step explanation:

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2 years ago
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