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Tpy6a [65]
3 years ago
9

Given that

Mathematics
1 answer:
slamgirl [31]3 years ago
3 0

Answer:

P=14

Step-by-step explanation:

Since P depends on two variables x and y as the sum of the two, then;

P = 3+ 11

P = 14

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Write both numbers as a product of prime numbers:

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Then GCF(56,96)=2³=8.

Now you can rewrite the sum 56+96 as following two factors:

56+96=8·7+8·12=8·(7+12)=8·19 (here the first factor os GCF and the secomd factor is  the sum of two numbers 7 and 12 that do not have a common factor).

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Differentiate Vx(x + 2) with respect to x.
Travka [436]

Answer:

y'= \frac{3x+2}{2\sqrt{x} }

General Formulas and Concepts:

<u>Calculus</u>

The derivative of a constant is equal to 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Product Rule: \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

y=\sqrt{x} (x+2)

<u>Step 2: Rewrite</u>

y=x^{\frac{1}{2} } (x+2)

<u>Step 3: Differentiate</u>

  1. Product Rule [Basic Power/Chain Rule]:                 y'= \frac{1}{2} x^{\frac{1}{2} -1}(x+2)+x^{\frac{1}{2} }(1)
  2. Simplify:                                                                            y'= \frac{1}{2} x^{\frac{-1}{2}}(x+2)+x^{\frac{1}{2}}
  3. Rewrite:                                                                                        y'= \frac{x+2}{2\sqrt{x} } + \sqrt{x}
  4. Add:                                                                                                       y'= \frac{3x+2}{2\sqrt{x} }
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