First, divide the fractions into a decimal format.
8/3=2.667
-11/3=-3.667
Second, find the placement of the decimal.
Write both numbers as a product of prime numbers:
Then GCF(56,96)=2³=8.
Now you can rewrite the sum 56+96 as following two factors:
56+96=8·7+8·12=8·(7+12)=8·19 (here the first factor os GCF and the secomd factor is the sum of two numbers 7 and 12 that do not have a common factor).
Answer: 56+96=8·19.
0.08 is 10 times greater than 0.008, becase 0.008 · 10 = 0.08
Answer:

General Formulas and Concepts:
<u>Calculus</u>
The derivative of a constant is equal to 0
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Product Rule: ![\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bf%28x%29g%28x%29%5D%3Df%27%28x%29g%28x%29%20%2B%20g%27%28x%29f%28x%29)
Chain Rule: ![\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%20%3Df%27%28g%28x%29%29%20%5Ccdot%20g%27%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>

<u>Step 2: Rewrite</u>

<u>Step 3: Differentiate</u>
- Product Rule [Basic Power/Chain Rule]:

- Simplify:

- Rewrite:

- Add:
