Answer:
4
Step-by-step explanation:
Class width is said to be the difference between the upper class limit and the lower class limit consecutive classes of a grouped data. To calculate class width, this formula can be used:
CW = UCL - LCL
Where,
CW= Class width
UCL= Upper class limit
LCL= Lower class limit
From the table above:
For class 1, CW = 64 - 60 = 4
For class 2, CW = 69 - 65 = 4
For class 3, CW = 74 - 70 = 4
For class 4, CW = 79 - 75 = 4
For class 5, CW = 84 - 80 = 4
Therefore, the class width of the grouped data = 4
Step-by-step explanation:
There are 12 games in the population. You need to use a random number generator to choose 2 of these games.
RandomSample[{1,2,3,4,5,6,7,8,9,10,11,12},2]
Let's say the first sample you get is {1,5}. That corresponds to game times of 8 minutes and 7 minutes. The mean game time for that sample is 7.5 minutes. So the first row in your table would be:
![\left[\begin{array}{ccc}Sample&List\ of\ Game\ Times&Mean\ Game\ Time\\1&8,7&7.5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7DSample%26List%5C%20of%5C%20Game%5C%20Times%26Mean%5C%20Game%5C%20Time%5C%5C1%268%2C7%267.5%5Cend%7Barray%7D%5Cright%5D)
Caca pipipoopoo checkkkkkkkk
Answer:
There are a total of 23 cars with air conditioning and automatic transmission but not power steering
Step-by-step explanation:
Let A be the cars that have Air conditioning, B the cars that have Automatic transmission and C the cars that have pwoer Steering. Lets denote |D| the cardinality of a set D.
Remember that for 2 sets E and F, we have that

Also,
|E| = |E ∩F| + |E∩F^c|
We now alredy the following:
|A| = 89
|B| = 99
|C| = 74

|(A \cup B \cup C)^c| = 24
|A \ (B U C)| = 24 (This is A minus B and C, in other words, cars that only have Air conditioning).
|B \ (AUC)| = 65
|C \ (AUB)| = 26

We want to know |(A∩B) \ C|. Lets calculate it by taking the information given and deducting more things
For example:
99 = |B| = |B ∩ C| + |B∩C^c| = 11 + |B∩C^c|
Therefore, |B∩C^c| = 99-11 = 88
And |A ∩ B ∩ C^c| = |B∩C^c| - |B∩C^c∩A^c| = |B∩C^c| - |B \ (AUC)| = 88-65 = 23.
This means that the amount of cars that have both transmission and air conditioning but now power steering is 23.
Parallel = same slope
Y = -3x + 7, the slope is -3
Slope intercept form: y = mx + b
Y = -3x + b
Plug in point (2,-4) and solve for b
-4 = -3(2) + b
-4 = -6 + b, b = 2
Solution: y = -3x + 2
The answer is D