Find the least common denominator for these fractions. Enter your answer in<br> the space provided.

so we have a small issue. I dont know how to figure this out and I dont know what equivalent means :/ so if you can help me that

Mars2501 [29]

Equivalent means "equal to"

Because we are looking for an equation that is not equivalent to 3y + x = 18, we need to find one that is not equal to 3y + x = 18.

First, lets try y = 6 - 1/3x

3y + x = 18

Divide the whole of both sides by 3

y + 1/3x = 6

Then, subtract 1/3x from each side

y = 6 - 1/3x

So, y = 6 - 1/3x IS equivalent to 3y + x = 18, so it is not the answer.

Next, lets try y - 5 = -1/3 (x - 3)

First, we need to distribute the -1/3 in the right side.

y - 5 = -1/3x + 1

Add 5 to each side

y = -1/3x + 6

Add 1/3x to each side

y + 1/3x = 6

So, y + 1/3x = 6 is NOT equivalent to 3y + x = 18, so it IS an answer.

Lets try the third one: y - 5 = 1/3(x + 3)

We need to use distributive property again on the right side

y - 5 = 1/3x + 1

Add 5 to each side

y = 1/3x + 6 is not equivalent to 3y + x = 18 so it IS and answer

Lets test the last one: 6y + 2x = 36

Divide the whole of each side by 2

3y + x = 18 IS equivalent to 3y + x = 18 so it is NOT an answer

4 0

3 years ago

The sum of two numbers is the same as four times the smaller number. If twice the larger is decreased by the smaller, the result

liraira [26]

The two numbers are 6 and 18

Step-by-step explanation:

The given is:

The sum of two numbers is the same as four times the smaller number
If twice the larger is decreased by the smaller, the result is 30

We need to find the the numbers

Assume that the smaller number is x and the larger number is y

∵ The smaller number = x

∵ The larger number = y

∵ The sum of the two numbers is the same as four times the

smaller number

- That means add the two numbers and equate the sum by four

times x

∴ x + y = 4x

- Subtract both sides by x

∴ y = 3x ⇒ (1)

∵ Twice the larger number is decreased by the smaller number,

the result is 30

- That means multiply y by 2 and subtract x from the product,

then equate the difference by 30

∴ 2y - x = 30 ⇒ (2)

- Substitute y in equation (2) by equation (1)

∵ 2(3x) - x = 30

∴ 6x - x = 30

- Add like terms in the left hand side

∴ 5x = 30

- Divide both sides by 5

∴ x = 6

- Substitute the value of x in equation (1) to find y

∵ y = 3(6)

∴ y = 18

The two numbers are 6 and 18

Learn more:

You can learn more about the system of equation in brainly.com/question/2115716

#LearnwithBrainly

5 0

3 years ago

A student and a professor each choose a number between 1 and 9 (1 and 9 are both possible choices). what is the probability that

olchik [2.2K]

I think the answer is 3/9

7 0

3 years ago

What is the recursive formula for this arithmetic sequence?<br> -7,-1,5, 11, ...

Serhud [2]

Answer:

D

Step-by-step explanation:

The recursive formula allows us to find any term in a sequence by adding the common difference d to the previous term.

Here d = - 1 - (- 7) = - 1 + 7 = 6 , then

$a_{n}$ = $a_{n-1}$ + 6 ; a₁ = - 7

4 0

3 years ago

The path of a softball thrown by maddie forms a parabola wirh the equation y=-3/2401(x-49)^2+8.5 how far does the ball travel ve

ExtremeBDS [4]

Answer:

The distance travelled by ball is 98 units before it again reaches the same height from which it was thrown.

Step-by-step explanation:

The given parabolic equation is

$y=-\frac{3}{2401}(x-49)^2+8.5$

Where, h is height of ball after covering x distance horizontally.

Put x=0, to find initial height of the ball.

$y=-\frac{3}{2401}(0-49)^2+8.5$

$y=-3+8.5$

$y=5.5$

Put y=5.5 in the given equation and find the values of x at which the height of ball is 5.5.

$5.5=-\frac{3}{2401}(x-49)^2+8.5$

$\frac{3}{2401}(x-49)^2=-5.5+8.5$

$\frac{3}{2401}(x-49)^2=3$

$(x-49)^2=2401$

Take square root both sides.

$x-49=\pm 49$

$x=\pm 49+49$

$x=0,98$

The height of ball is 5.5 at x=0 and x=98.

Therefore distance travelled by ball is 98 units before it again reaches the same height from which it was thrown.

7 0

3 years ago

Find the least common denominator for these fractions. Enter your answer in the space provided.