We know that this is a parabola, as the equation is denoted by the x^2 term.
We can see that the symmetry is seen at the point -0.5, therefore making the axis of symmetry the vertical line -0.5.
The vertex is found in quadrant three. In other words, it will shift by a negative value both horizontally and vertically. The vertex is therefore (-0.5, -0.5).
We can verify this in the equations by using the formula (-b/2a) to find the vertex. The only quadratic equation that satisfies this is -2x^2 + 2x -1.
To sum it up, the answers are:
-2x^2 + 2x - 1.
AoS: x = -0.5
Vertex: (-0.5, -0.5).
X^3 + 5^3
(x+5)x(x^2-X x 5+5^2)
(x+5)x(x^2 -5x+5^2)
(x+5)x(x^2 -5x+25)
(x+5) x (x^2 -5x+25)
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