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2 answers:
Hello!
We will put the x value into the second equation and solve below.
2(-3y-13)+2y=-6
-6y-26+2y=-6
-4y-26=-6
-4y=20
y=-5
We will know put our y value into the first equation to find x.
x==-3(-5)-13
x=15-13
x=2
Just to check we will put our two values into the second equation and see if it is true.
4+-10=-6
-6=-6
----------------------------------------------------------
I hope this helps!
We will put the x value into the second equation and solve below.
2(-3y-13)+2y=-6
-6y-26+2y=-6
-4y-26=-6
-4y=20
y=-5
We will know put our y value into the first equation to find x.
x==-3(-5)-13
x=15-13
x=2
Just to check we will put our two values into the second equation and see if it is true.
4+-10=-6
-6=-6
----------------------------------------------------------
I hope this helps!
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about the second one... well, is a "fait accompli" that using the pythagorean theorem, if x = 8 and y = 5, the hypotenuse must be √(8² + 5²) = √(89), which is neither of those choices.
5, 8, 13 are no dice, namely 5² + 8² ≠ 13
25, 64, 17 is are no dice too, because 25² + 17² ≠ 64²
however, 5,12 and 13 are indeed a pythagorean triple
also is 39, 80, 89.
when looking for a pythagorean triple, recall that c² = a² + b².
so the longest leg is the sum of the square of the small ones.
so what you'd do is, check the small legs, square them, add them up, if they're indeed a pythagorean triple, they "must" add up to the longest leg.
