<h2><u>
PLEASE MARK BRAINLIEST!</u></h2>
Answer:
Let's see...
Step-by-step explanation:
*Note: we can't find the exact area of the shaded figure right off the bat, we have to find the area of a bigger figure and divide it by 2.
<h3>The coordinates of the bigger figure:</h3>
A = (0,0)
B' = (0,4)
C = (5,4)
D' = (5,0)
Note: the little [ ' ] next to the B and D indicate that it is not the same coordinate as B and D, just that those points would be the same as point B and D.
<h3>That being said, what is the area of the bigger figure?</h3>
A = l * w
A = 4 * 5
A = 20 units²
<h3>Now, divide the Area by 2:</h3>
A = 20 ÷ 2
<em>A = 10 units²</em>
I hope this helps!
- sincerelynini
3 boxes of 12″ =36 = 2 boxes of 18″
so shortest height at which the 2 stack will be the same height =36 inches
Answer:
The degrees of freedom are given by;
The significance level is 0.1 so then the critical value would be given by:
If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays
Step-by-step explanation:
For this case we have the following observed values:
Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100
For this case the expected values for each day are assumed:
The statsitic would be given by:
Where O represent the observed values and E the expected values
The degrees of freedom are given by;
The significance level is 0.1 so then the critical value would be given by:
If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays
4x + 25 + x - 15
5x + 10
/ 5 / 5
x = 2
Refer Back To The First Problem To Solve The Second One, You Are Doing Great!
Answer:
Send what?
Step-by-step explanation:
I need a better question
