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iren2701 [21]
3 years ago
14

Calculate the HCF of 8a³-27, 4a²-9 and 4a²-12a+9​

Mathematics
1 answer:
Lyrx [107]3 years ago
7 0

\:  \:  \:  \:  \:

first add

(3a²-5a+5)+(a³-5a²+8)

=3a²-5a+5+a³-5a²+8

=a³-2a3a²-5a²+5+8

=a³-2a²+13

and now,

substract a³-2a²+13 from a²-4a²-9

=7a²-4a²-9-(a³+13)

=7a²-4a²-9-a³+2a²-13

= a³+7a²-4a²+2a²-9-13

=-a³+5a²-22

<h2><u>hope</u><u> it</u><u> helps</u></h2>

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