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3 years ago

2x+3(-6x-2)=18 Solve for X

Mathematics

2 answers:

Lelechka [254]3 years ago

6 0

Answer:

x = - 3/2

(the dash by the 3/2 is to show that it is negative, and is part of the answer)

pishuonlain [190]3 years ago

3 0

Answer:

x= -3/2

Step-by-step explanation:

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prisoha [69]

Answer:

D = 59t

P = 42t

5 hours after noon, darmian is 17 miles closer to the stadium than paisley

Step-by-step explanation:

At noon, Damian is 383 miles away from the stadium and paisley is 315 miles away from the stadium.

Now, we are told that damians speed is 59 mph while paisley's speed is 42 mph.

At t hours after noon, their distance covered will be;

Damian; D = 59t

Paisley; P = 42t

This is because distance = speed × time

Now, 5 hours after noon, their respective distance covered will be;

D(5) = 59 × 5 = 295 miles

P(5) = 42 × 5 = 210 miles

This means that;

distance of Damian from the stadium is; 383 - 295 = 88 miles

Distance of paisley from the stadium is;

315 - 210 = 105 miles

Difference in their distances to the stadium = 105 - 88 = 17 miles

Thus, 5 hours after noon, darmian is 17 miles closer to the stadium than paisley

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Read 2 more answers

XY is a diameter of a circle and Z is a point on the circle such that ZY=6. If the area of the triangle XYZ is 18 square root 3

nataly862011 [7]

<h2>Answer:</h2>

4π

<h2>Step-by-step explanation:</h2>

As shown in the diagram, triangle XYZ is a right triangle. Therefore, its area (A) is given by:

A = $\frac{1}{2}$ x b x h -------------(i)

Where;

A = 18 $\sqrt{3}$

b = XZ = base of the triangle

h = YZ = height of the triangle = 6

<em>Substitute these values into equation(i) and solve as follows:</em>

18 $\sqrt{3}$ = $\frac{1}{2}$ x b x 6

18 $\sqrt{3}$ = 3b

<em>Divide through by 3</em>

6 $\sqrt{3}$ = b

Therefore, b = XZ = 6 $\sqrt{3}$

<em>Now, assume that the circle is centered at O;</em>

Triangle XOZ is isosceles, therefore the following are true;

(i) |OZ| = |OX|

(ii) XZO = ZXO = 30°

(iii) XOZ + XZO + ZXO = 180° [sum of angles in a triangle]

=> XOZ + 30° + 30° = 180°

=> XOZ + 60° = 180°

=> XOZ = 180° - 60°

=> XOZ = 120°

Therefore we can calculate the radius |OZ| of the circle using sine rule as follows;

$\frac{sin|XOZ|}{XZ} = \frac{sin|ZXO|}{OZ}$

$\frac{sin120}{6\sqrt{3} } = \frac{sin 30}{OZ}$

$\frac{\sqrt{3} /2}{6\sqrt{3} } = \frac{1/2}{|OZ|}$

$\frac{1}{12} = \frac{1}{2|OZ|}$

$\frac{1}{6} = \frac{1}{|OZ|}$

|OZ| = 6

The radius of the circle is therefore 6.

<em>Now, let's calculate the length of the arc XZ</em>

The length(L) of an arc is given by;

L = θ / 360 x 2 π r ------------------(ii)

Where;

θ = angle subtended by the arc at the center.

r = radius of the circle.

In our case,

θ = ZOX = 120°

r = |OZ| = 6

Substitute these values into equation (ii) as follows;

L = 120/360 x 2π x 6

L = 4π

Therefore the length of the arc XZ is 4π

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3 years ago