First, solve for y
4y+3≤y+6
3y+3<span>≤6
3y</span><span>≤3
y</span><span>≤1
the third picture is the correct graph</span>
1
Split the second term into two terms
2{x}^{2}+3x-2x-32x2+3x−2x−3
2 Factor out common terms in the first two terms, then in the last two terms<span>x(2x+3)-(2x+3)<span>x(2x+3)−(2x+3)</span></span>
3 Factor out the common term 2x+32x+3<span><span>(2x+3)(x-1)<span>(2x+3)(x−1)</span></span><span>
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M with 2 as it's exponent - n with 3 as it's exponent = 16
Answer: x < -1
Step-by-step explanation:
•Solve:
x + 6 < 5
• Subtract 6 on both sides:
x + 6 < 5
-6 -6
—————-
• Result:
x < -1