Answer:
I think the answer is -104,400,000,000,000,000
Step-by-step explanation:
QUESTION:
The code for a lock consists of 5 digits (0-9). The last number cannot be 0 or 1. How many different codes are possible.
ANSWER:
Since in this particular scenario, the order of the numbers matter, we can use the Permutation Formula:–
- P(n,r) = n!/(n−r)! where n is the number of numbers in the set and r is the subset.
Since there are 10 digits to choose from, we can assume that n = 10.
Similarly, since there are 5 numbers that need to be chosen out of the ten, we can assume that r = 5.
Now, plug these values into the formula and solve:
= 10!(10−5)!
= 10!5!
= 10⋅9⋅8⋅7⋅6
= 30240.
Answer: 5¹ + 5² + 5³, 130 students
<u>Step-by-step explanation:</u>
Monday: 1 1 1 1 1 = 5 ⇒ 5¹
+ Tuesday: 1(5) 1(5) 1(5) 1(5) 1(5) = + 25 ⇒ 5²
+ Wednesday:5(5) 5(5) 5(5) 5(5) 5(5) = <u>+125 </u>⇒ 5³
130
Extra Credit: How many students will know the rumor on Thursday? 5¹ + 5² + 5³ + 5⁴
Answer is 9/4 (last choice)
cause
slope = (-6-3)/(-2-2) = -9/-4 = 9/4
Answer:
I believe it is C
Step-by-step explanation:
Sorry if I got it wrong but hopefully you got it right