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andre [41]
3 years ago
11

Is there a solution for (2x-4) ≥ -10

Mathematics
1 answer:
Effectus [21]3 years ago
4 0
2x-4≥-10  add 4 to both sides

2x≥-6  divide both sides by 2

x≥-3

There are infinitely many solutions as x=[-3, +oo)
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What is the equation of the line that passes through the point (-6, -8) and has a slope of 1/3
ivanzaharov [21]

Answer <u>(assuming it can be in point-slope form)</u>:

y + 8 = \frac{1}{3} (x+6)

Step-by-step explanation:

With the given information, we can use the point-slope formula, y-y_1 = m (x-x_1), to write the equation of the line. Substitute values for the m , x_1, and y_1 in the formula to do so.

The m represents the slope, so substitute \frac{1}{3} in its place. The x_1 and y_1 represent the x and y values of one point the line intersects, so substitute -6 for x_1 and -8 for y_1. This gives the following answer and equation (just make sure to convert the double negatives into positives:  

y-(-8) = \frac{1}{3} (x-(-6))\\y + 8 = \frac{1}{3} (x+6)

3 0
2 years ago
Read 2 more answers
Will mark Brainlest help me to find the value of x (step by step) pls​
podryga [215]

Answer:

5 (cm)

Step-by-step explanation:

1. according to the condition in ΔABC: AC=BC, m∠C=90°. Then m∠B=m∠A=45° and

2. x=AC=AB/√2; ⇔ x=5 (cm).

4 0
3 years ago
Read 2 more answers
I NEED HELP! PLEASE HELP!
Amanda [17]

Answer:

2400 mm

Step-by-step explanation:

(80 x 60) - (60 x 40)

7 0
3 years ago
How do you find vertical, horizontal and oblique asymptotes for f(x) = (5x-15 )/ (2x 14)?
Andrei [34K]
For vertical asymptotes, find the values which make the function indetermine in this case x=-7,so this is the only vertical asymptote.
For horizontal asymptotes, find the limit when x tends to infinity:
=(5x/x-15/x)/(2x/x+14/x) = 5/2, this is the horizontal asymptote y=5/2
For obliques, you have to meet the degree of the numerator is exactly a greater degree than the denominator, in this case they are the same degree so no oblique asymptote.
6 0
3 years ago
The number of boots that 25 students had in their homes in Florida were recorded
wolverine [178]

Answer:

Min = 0; Q₁ = 0; Median = 2; Q₃ = 2; Max = 8

Step-by-step explanation:

Assume that your sorted data are

0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 4, 5, 8

1. Minimum

Min = 0

2. Median

The median is the middle value in a sorted data set. There are 25 items, so the median is the 13th item.

Median = 2

3. First quartile

Q₁ is the median of the lower half of the data set.

The median of 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 2 is 0.

Q₁ = 0

4. Third quartile

Q₃ is the median of the upper half of the data set.

The median of 2, 2, 2, 2, 2, 3, 3, 3, 3, 4, 5, 8 is 3.

Q₃ = 3

5. Maximum

Max = 8

7 0
2 years ago
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