Answer:
7) C) PQR ≈ TSR
8) B) 3
9) D) 102 ft
10) D) 21
11) C) 45
Step-by-step explanation:
7) C) PQR ≈ TSR
8) 2 * 6 = 12
so 4x = 12
x = 3
9)
24/20 = x/85
x = 24 * 85 / 20
x = 202 ft
10)
QT/35 = 24/40
QT/35 = 3/5
QT = 35 * 3 / 5
QT = 21
11)
ΔKLM ≈ΔXYZ
9/4 = 2.25
So
XY = 9 ---> given
YZ = 7 * 2.25 = 15.75
XZ = 9 * 2.25 = 20.25
Perimeter ΔXYZ = 9 + 15.75 + 20.25 = 45
Step-by-step explanation:
Distribute:
=−x2+−4x+−4+7
Combine Like Terms:
=−x2+−4x+−4+7
=(−x2)+(−4x)+(−4+7)
=−x2+−4x+3
Answer:
=−x2−4x+3
Rewrite the equations of the given boundary lines:
<em>y</em> = -<em>x</em> + 1 ==> <em>x</em> + <em>y</em> = 1
<em>y</em> = -<em>x</em> + 4 ==> <em>x</em> + <em>y</em> = 4
<em>y</em> = 2<em>x</em> + 2 ==> -2<em>x</em> + <em>y</em> = 2
<em>y</em> = 2<em>x</em> + 5 ==> -2<em>x</em> + <em>y</em> = 5
This tells us the parallelogram in the <em>x</em>-<em>y</em> plane corresponds to the rectangle in the <em>u</em>-<em>v</em> plane with 1 ≤ <em>u</em> ≤ 4 and 2 ≤ <em>v</em> ≤ 5.
Compute the Jacobian determinant for this change of coordinates:

Rewrite the integrand:

The integral is then

First one and the last one are rational. And the other two of them are irrational.
Y=3/1x+-1 hope this is correct