Maximum height is at dH/dt=0
H= -16T^2+80T+5
dH/dt=-32T+80
-32T+80=0
32T=80
T=2.5s when height is max
Hmax=-16(2.5)^2+80*2.5)+5
=105ft
catching the ball at 5' means solve for T at H=5
H= -16T^2+80T+5=5
-16T^2+80T=0
-16T(T-5)=0
so T=0 cannot be the ans or T=5s
Yes the sailfish can swim one mile
Answer:
y = -4/5x + 2/5
Step-by-step explanation:
Answer:
im confused?
Step-by-step explanation:
could you please rewrite this question? what are the numbers for?
1+1= 2
Big brain >:3 Ty for the points tho ^^
