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Alenkasestr [34]
2 years ago
8

Which expression below is equivalent to 4/5(1 1/4x + 3 1/3 )

Mathematics
1 answer:
zysi [14]2 years ago
4 0
First, change the mixed numbers into improper fractions: 1 1/4 —> 5/4 and 3 1/3 —> 10/3

rewrite equation: 4/5(5/4x + 10/3) and then distribute to 4/5(5/4x) + 4/5(10/3) = 20/20x + 40/15

simplify the sum: x + 8/3

convert 8/3 to a mixed number: 2 2/3


final answer: B. x + 2 2/3
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• The perimeter of a rectangular field is 118 meters.
Alex73 [517]

Answer:

101 meter

Step-by-step explanation:

I think

6 0
3 years ago
Simplify the following problem.<br> (-8+61) +(6+61)
Travka [436]

Answer: -8+61 = 53 and 6+61 = 67

3 0
3 years ago
The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f
WITCHER [35]

Answer:

Part 1) A=36(\pi-2)\ cm^2

Part 2) P=6(\pi+2\sqrt{2})\ cm

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)

we have that the base and the height of triangle is equal to the radius of the circle

r=12\ cm\\b=12\ cm\\h=12\ cm

substitute

A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2

simplify

Factor 36

A=36(\pi-2)\ cm^2

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r

substitute the given values

C=\frac{1}{2}\pi (12)\\C=6\pi\ cm

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm

simplify

AC=12\sqrt{2}\ cm

Find the perimeter

P=(6\pi+12\sqrt{2})\ cm

simplify

Factor 6

P=6(\pi+2\sqrt{2})\ cm

4 0
3 years ago
The function h(t) = –16t2 + 96t + 6 represents an object projected into the air from a cannon. The maximum height reached by the
jolli1 [7]
If you've started pre-calculus, then you know that the derivative of  h(t)
is zero where h(t)  is maximum.

The derivative is            h'(t) = -32 t  +  96 .

At the maximum ...        h'(t) = 0

                                       32 t = 96 sec

                                           t  =  3 sec . 
___________________________________________

If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.

In that case, the question GIVES you the maximum height.
Just write it in place of  h(t), then solve the quadratic equation
and find out what  't'  must be at that height.

                                       150 ft = -16 t²  +  96  t  +  6 

Subtract 150ft from each side:    -16t²  +  96t  -  144  =  0 .

Before you attack that, you can divide each side by  -16,
making it a lot easier to handle:

                                                         t²  -  6t  +  9  =  0

I'm sure you can run with that equation now and solve it.    
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.  
(Funny how the two widely different methods lead to the same answer.)

The answer is from AL2006

6 0
3 years ago
Which describes the graph of mc014-1.jpg on [0, 3)? The steps are at –2 from 0 to 1, at –1 from 1 to 2, and at 0 from 2 to 3. Th
Strike441 [17]
1) The graph consists of three horizontal segments, with discontinuities (jumps) at x = 1, x = 2, and x = 3. 
A horizontal segment at y = - 2 for the values x = 0 to 1.
A horizontal segment at y = - 1 for values x = 1 to 2
A horizontal segment at y = 0 for values x - 2 to 3.


2) To know whether the end points of a segment are defined by the left or the right values you have to look for the circle at the extreme of the segment: if it is a solid dot, means that the end is included, if is is an open circle (white inside) then the end is not included in that segment.

3)  That function is based on the function named integer part because if relates y with the integer part of x.

The integer value function is [x] and it makes correspond y values witht he integer values of x.:

y = 0 witht the integer value of x for x between 0 and 1, excluding 1.

y = 1 with the integer value of x between 1 and 2 (excluding 2)

y = 2 with the integer value of x between 2 and 3 (excluding 3)
y = 3 with the integer value of x between 3 and 4 (excluding 4)

But our function is two units below, so it is [x] - 2
8 0
3 years ago
Read 2 more answers
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