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Lilit [14]
2 years ago
14

a bookcase is to be constructed as shown in the figure below. the height of the bookcase is 2 feet longer than the length of a s

helf. if 22 feet of lumber is available for the entire unit including the shelves but NOT the back of the bookcase find the length and height of the unit.

Mathematics
1 answer:
In-s [12.5K]2 years ago
4 0

The length of the shelf is 10 feet while its height is 10 feet.

<h3>Equation</h3>

Equation is an expression used to show the relationship between the sides and angles of a right angled triangle.

Let x represent the shelf length and y represent the shelf height.

The height of the bookcase is 2 feet longer than the length of a shelf. hence:

  • y = x + 2
  • -x + y = 2   (1)

Also, 22 feet of lumber is available:

  • x + y = 22   (2)

From equation 1 and 2:

y = 12, x = 10

The length of the shelf is 10 feet while its height is 10 feet.

Find out more on equation at: brainly.com/question/13763238

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(2x^9y^n) (4x²y^10)-8x^11 y^20                        i say the answer 1 or 10

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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1

2

10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

10

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(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

1

2

10

30

(2x^9y^n) (4x²y^10)-8x^11 y^20

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10

30

4 0
1 year ago
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Answer:

3

Step-by-step explanation:

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4 0
2 years ago
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Answer: hey I actually just finished learning about this in math.

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