Question

Match each quadratic equation with its solution set.

Answer 1

Answer:

( 8 , - 8)  => x² - 55 = 9

( 4 , - 4)  =>  2x² - 32 = 0

(5 , - 5) => 4x² - 100 = 0

(11 , - 11) => x² - 140 = -19

( 3, - 3) =>  2x² - 18 = 0

Step-by-step explanation:

1)

$2x^2 - 32 = 0\\\\2(x^2 - 16 ) = 0 \\\\x^2 - 16 = 0 \\\\x^2 = 16 \\\\x = \sqrt {16 } = \pm 4$

x = ( 4 , - 4)

2)

$4x^2 - 100 = 0 \\\\4(x^2 - 25 ) = 0\\\\x^2 - 25 = 0 \\\\x^2 = 25 \\\\x= \sqrt{25} = \pm 5$

x = ( 5 , - 5 )

3)

$x^2 - 55 = 9 \\\\x^2 = 9 +55\\\\x^2 = 64\\\\x = \sqrt{64} = \pm 8$

x= ( 8 , - 8)

4)

$x^2 - 140 = - 19\\\\x^2 = -19 + 140 \\\\x^2 = 121 \\\\x= \sqrt{121} = \pm 11$

x = ( 11  , -11)

5)

$2x^2 - 18 = 0\\\\2(x^2 - 9) = 0\\\\x^2- 9 = 0 \\\\x^2 = 9 \\\\x = \sqrt9 = \pm 3$

x = ( 3 , - 3)

Answer 2

Answer:     2x^2-32=0         ⇒ (-4,4)

                 4x^2-100=0        ⇒ (-5 ,5)

                 x^2-55=9            ⇒(-8,8)

                  x^2-140=-19        ⇒(-11,11)

Step-by-step explanation:

2x^2-32=0

2x^2=32

x^2=16

x=±4

4x^2-100=0

4x^2=100

x^2=25

x=±5

2x^2-18=0

2x^2=18

x^2=9

x=±3

x^2-55=9

x^2=64

x=±8

x^2-140=-19

x^2=121

x=±11