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3 years ago

A) write the measurement 3086 ml into the place value table below

Mathematics

1 answer:

Mumz [18]3 years ago

7 0

Answer:

3086 ml ÷ 1000 = 3.086

9 cm × 10 = 90mm

9 cm ÷ 100 = 9m

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4.6x-9.3=27.5 NEED HELP asap

gavmur [86]

Answer:

x=8

Step-by-step explanation:

4.6x-9.3=27.5

+9.3 +9.3

-------------------------

4.6x=35.8

4.6x/4.6 35.8/4.6

x=8

3 0

3 years ago

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Divide 254 by 11.8. round your answer to the nearest hundredth.

Olin [163]

The answer is 21.52 so I hope that helped

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4 years ago

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. Find the area of the regular dodecagon inscribed in a circle if one vertex is at (3, 0).

devlian [24]

Answer:

Area of the regular dodecagon inscribed in a circle will be 27 square units.

Step-by-step explanation:

A regular dodecagon is the structure has twelve sides and 12 isosceles triangles inscribed in a circle as shown in the figure attached.

Since angle formed at the center by a polygon = $\frac{360}{n}$

Therefore, angle at the center of a dodecagon = $\frac{360}{12}$ = 30°

Since one of it's vertex is (3, 0) therefore, one side of the triangle formed or radius of the circle = 3 units

Now area of a small triangle = $\frac{1}{2}.(a).(b).sin\theta$

where a and b are the sides of the triangle and θ is the angle between them.

Now area of the small triangle = $\frac{1}{2}.(3).(3).sin30$

= $\frac{9}{4}$

Area of dodecagon = 12×area of the small triangle

= 12× $\frac{9}{4}$

= 27 unit²

Therefore, area of the regular octagon is 27 square unit.

4 0

3 years ago

Find all the missing dimensions when a=9, b=13, c=64°

DerKrebs [107]

Answer:

Part 1) $c=12.14\ units$

Part 2) $m\angle A=41.78^o$

Part 3) $m\angle B=74.22^o$

Step-by-step explanation:

step 1

Find the measure of side c

Applying the law of cosines

$c^2=a^2+b^2-2(a)(b)cos(C)$

we have

$a=9\ units\\b=13\ units\\C=64^o$

substitute

$c^2=9^2+13^2-2(9)(13)cos(64^o)$

$c^2=81+169-234cos(64^o)$

$c^2=250-234cos(64^o)$

$c^2=147.4212$

$c=12.14\ units$

step 2

Find the measure of angle A

Applying the law of sines

$\frac{a}{sin(A)}=\frac{c}{sin(C)}$

substitute the given values

$\frac{9}{sin(A)}=\frac{12.14}{sin(64^o)}$

solve for sin(A)

$sin(A)=\frac{sin(64^o)}{12.14}(9)$

$sin(A)=0.6663$

$m\angle A=sin^{-1}(0.6663)=41.78^o$

step 3

Find the measure of angle B

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

$m\angle A+m\angle B+m\angle C=180^o$

substitute the given values

$41.78^o+m\angle B+64^o=180^o$

$m\angle B+105.78^o=180^o$

$m\angle B=180^o-105.78^o$

$m\angle B=74.22^o$

5 0

3 years ago

Determine whether Salvador's answers and work are correct. If ether answer is incorrect,

Neko [114]

Answer:

His first answer is wrong.

Step-by-step explanation:

The bar should only be over the 6 since it is the only number repeating.

6 0

3 years ago