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2 years ago

Given the function f(x) = x - 10, what is the corresponding value when x = -12? *

Mathematics

1 answer:

Dahasolnce [82]2 years ago

4 0

Answer:

-22

Step-by-step explanation:

-12 - 10 = -22

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In the system of equations below, which variable would it be easiest to solve for?

Maru [420]

Answer:

<h3> The first: The easiest to solve for is x in the first equation.</h3>

Step-by-step explanation:

To get x from first equation you just need to subtract 4y from both sides.

The rest of variables needs two operations to get variable - subtracting and then dividing.

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2 years ago

Read 2 more answers

14. Find the distance between p1(7, 217/180pi) and p2(5, -23/36pi) ) on the polar plane. (Show work)

Goshia [24]

Answer:

c 3/4

Step-by-step explanation:

the slope of the line is

m = (y2-y1)/(x2-x1)

= (-2--5)/(6-2)

= (-2+5)/(6-2)

=3/4

happy to help mark me as brainliest pls

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3 years ago

Complete the table for the relationship shown in the graph

Sonja [21]

Answer:

where ?

Step-by-step explanation:

where is the question to solve ?

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3 years ago

Betty draws cards randomly from a box containing 8 cards of the same shape and size. There is 2 red cards, 3 blue cards, and 3 y

saveliy_v [14]

Answer:

i think you have to add all the numbers then divide

Step-by-step explanation:

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3 years ago

What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where

Setler79 [48]

Answer:

$k=-16,k=-8,k=8,k=16$

Step-by-step explanation:

We are given quadratic equations as

$x^2+kx+15$

and it can be factored as

$=(x+a)(x+b)$

now, we can multiply factor term

$(x+a)(x+b)=x^2+(a+b)x+ab$

now, we can compare

$x^2+(a+b)x+ab=x^2+kx+15$

so, we get

$k=a+b$

$ab=15$

we are given that

'a' and 'b' are integers

so, we can find all possible factors

$15=(-1\times -15),(1\times 15)$

$15=(-3\times -5),(3\times 5)$

so, we can find k

At $(-1\times -15)$ :

$k=a+b$

we can plug values

$k=-1-15$

$k=-16$

At $(1\times 15)$ :

$k=a+b$

we can plug values

$k=1+15$

$k=16$

At $(-3\times -5)$ :

$k=a+b$

we can plug values

$k=-3-5$

$k=-8$

At $(3\times 5)$ :

$k=a+b$

we can plug values

$k=3+5$

$k=8$

So, values of k are

$k=-16,k=-8,k=8,k=16$

6 0

3 years ago