Answer: 3 - x
Step-by-step explanation: With
Subtraction be careful. 3 - x is not the same as x - 3. You have to keep the values given in order.
Answer:
Step-by-step explanation:
<u>Figure 1</u>
<u>Figure 2</u>
<u>Figure 3</u>
<u>Equation for nth term</u>
- (n + 1)^2 - 2 =
- n^2 + 2n + 1 - 2 =
- n^2 + 2n - 1
Answer: 
Step-by-step explanation:
The equation of a circle in the general form is:

The equaton of a circle in standard form is:

Where the center is at <em>(h, k)</em> and <em>r</em> is the radius
To write the equation of a circle from general form to standard form, you must complete the squaare, as you can see below:
1- Given the equation in general form:

2- Complete the square:
-Group the like terms and move the constant to the other side.
- Complete the square on the left side of the equation.
- Add the same value to the other side.
Then you obtain:

The answer is 0
Explanation
When doing PEMDAS you always move from left to right
4+7=11
-5-6=-11
11-11
= 0
Answer:
d 380
Step-by-step explanation: