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Natalija [7]
2 years ago
11

Draw the region that satisfies all three of the inequalities; x < 3, y > 2, y < 2x+3​

Mathematics
1 answer:
FrozenT [24]2 years ago
3 0

Check the picture below.

the line you drew for y = 2x +3 is correct, now recall that the line for x = 3 is just a vertical line, in red, and that y = 2 is just a horizontal line, in green.

now all lines are solid because all are using ⩽ or ⩾, meaning the borderline is included, and you can do a "true" "false" region check if you wish, but less than 3 is to the left of the red one, greater than 2 is above the green one and less than 2x + 3 is just to its left.

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We have some number x and we divide that by 18. The result is larger than 27. To find possible values for x, we need to undo what is happening to x. The opposite of division is multiplication. We multiply both sides by 18 to cancel out the "18" on the left side, which will isolate x to get it to its own side.

This is what the steps look like

x/18 > 27

18*( x/18 ) > 18*27 .... multiplying both sides by 18

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Find the coordinates of the intersection of the diagonals of parallelogram GHJK with vertices G(0,2), H(4,2), J(3,0), and K(-1,0
zimovet [89]

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(1.5,1)

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The midpoint of the two midpoints is (1.5,1)

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