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Natalija [7]
3 years ago
11

Draw the region that satisfies all three of the inequalities; x < 3, y > 2, y < 2x+3​

Mathematics
1 answer:
FrozenT [24]3 years ago
3 0

Check the picture below.

the line you drew for y = 2x +3 is correct, now recall that the line for x = 3 is just a vertical line, in red, and that y = 2 is just a horizontal line, in green.

now all lines are solid because all are using ⩽ or ⩾, meaning the borderline is included, and you can do a "true" "false" region check if you wish, but less than 3 is to the left of the red one, greater than 2 is above the green one and less than 2x + 3 is just to its left.

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The trig functions that you need to deal with are
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Cosine
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To make this as simple as possible, the first thing I would do is look up the values of these functions and identify which ones are equal to either 1/2 or 1.0 or 2.0

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Now it is up to you to figure out how to combine all six trig functions so that they equal zero. There are many possibilities for you to choose from..
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Step-by-step explanation:

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