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3 years ago

Complete the solution of the equation find the value of Y when X equals -8. 4x+9y=-14

Mathematics

1 answer:

lukranit [14]3 years ago

4 0

Answer:

$\large\boxed{y=2}$

Step-by-step explanation:

In this question, we're going to solve the equation.

What we would do is plug in the given information in the right variable. In this case, we would plugin -8 to x, since x = -8

We are solving for y, so we would nee to find how much y = ?

Your equation should look like this:

$4(-8)+9y=-14$

Lets solve:

$4(-8)+9y=-14\\\\\text{Multiply}\, 4(-8)\\\\-32+9y=-14\\\\\text{Add 32 to both sides}\\\\9y=18\\\\\text{Divide}\\\\y=2$

When you're done solving, you should get y = 2

This means that y = 2

<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>

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Who knows this, Find m∠UTS, if m∠UTV=x+15, m∠VTS=140∘, and m∠UTS=15x+15

kakasveta [241]

Answer:

165

Step-by-step explanation:

First, m<UTS=m<UTV+m<VTS by Angle Addition Postulate. Then, you substitute all the values that you provided for the angles. 15x+15=x+15+140. You then solve for x.

15x+15=x+155

14x=140

x=10

You then plug back in 10 for X in the value of m<UTS. 15(10)+15=165

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3 years ago

A rectangle has a perimeter of 36 inches and a width of 10 inches. What is the length of the rectangle?

leonid [27]

Answer:

Step-by-step explanation:

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3 years ago

Algebra 1 Please help! thank u sm

olga_2 [115]

Answer:

1. Slyvia is wrong. You treat the numbers normally when dividing the left side, so 3.61/4.1 = .88. When dividing the exponents, you subtract the numerator from the denominator, so -11-7 = -18. So, you do have .88 * 10^-18, at first, but when you are working in scientific notation you want the decimal to be greater than so, which requires us to add an additional -1, to make it 8.8 instead of 0.88. This is because we want to move the decimal place left one more time. This results in our final answer being 8.8 * 10^-19, which is not Slyvia's answer.

2. Dylan's answer is correct. He subtracted the exponents correctly, then moved the decimal place over one place towards the left.

3. Ethan is wrong. He added the exponents, instead of subtracting. However, you cannot do this, because when you are dividing exponents, you must subtract.

Step-by-step explanation:

I have this acronym I learned called MADSPM, which has helped me a lot. I never learned it in Algebra, but I wish that they had taught it. Each letter corresponds with an exponent rule. If this makes sense, here is what it stands for:

When you multiply, you add.

When you divide, you subtract.

When there are parentheses, you multiply.

In this case, it was solely division. So, you just need to remember division = subtraction, when it comes to exponents.

Hopefully this helped. If you need me to explain it better, please let me know, and I will try. Thanks much & have a wonderful day!

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3 years ago

Approximate the real zeros of f(x) = x2 + 3x + 1 to the nearest tenth

pshichka [43]

Approximate the real zeros of f(x) = x2 + 3x + 1 to the nearest tenth

<u>C. 2.6,-0.4</u>

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3 years ago

Read 2 more answers

A rectangular swimming pool is bordered by a concrete patio. the width of the patio is the same on every side. the area of the s

andre [41]

Answer:

$x = \frac{1}{4}\left(-(l + w) + \sqrt{l^2 + 6lw + w^2} \right)$

where

l = length of the pool (w/o the patio)
w = width of the pool (w/o the patio)

Explanation:

Let

x = width of the patio
l = length of the pool (w/o the patio)
w = width of the pool (w/o the patio)

Since the pool is bordered by a complete patio,

Length of the pool (with the patio)
= (length of the pool (w/o the patio)) + 2*(width of the patio)
Length of the pool (with the patio) = l + 2x

Width of the pool (with the patio)
= (width of the pool (w/o the patio)) + 2*(width of the patio)
Width of the pool (with the patio) = w + 2x

Note that

Area of the pool (w/o the patio)
= (length of the pool (w/o the patio))(width of the pool (w/o the patio))
Area of the pool (w/o the patio) = lw

Area of the pool (with the patio)
= (length of the pool (w/o the patio))(width of the pool (w/o the patio))
= (l + 2x)(w + 2x)
= w(l + 2x) + 2x(l + 2x)
= lw + 2xw + 2xl + 4x²
Area of the pool (with the patio) = 4x² + 2x(l + w) + lw

Area of the patio
= (Area of the pool (with the patio)) - (Area of the pool (w/o the patio))
= (4x² + 2x(l + w) + lw) - lw
Area of the patio = 4x² + 2x(l + w)

Since the area of the patio is equal to the area of the surface of the pool, the area of the patio is equal to the area of the pool without the patio. In terms of the equation,

Area of the patio = Area of the pool (w/o the patio)
4x² + 2x(l + w) = lw
4x² + 2x(l + w) - lw = 0 (1)

Let

a = numerical coefficient of x² = 4
b = numerical coefficient of x = 2(l + w)
c = constant term = -lw

Then using quadratic formula, the roots of the equation 4x² + 2x(l + w) - lw = 0 is given by

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\\ = \frac{-2(l + w) \pm \sqrt{(2(l + w))^2 - 4(4)(-lw)}}{2(4)} 
\\ = \frac{-2(l + w) \pm \sqrt{(4(l + w)^2) + 16lw}}{8} 
\\ = \frac{-2(l + w) \pm \sqrt{(4(l^2 + 2lw + w^2) + 4(4lw)}}{8}
\\ = \frac{-2(l + w) \pm \sqrt{(4(l^2 + 2lw + w^2 + 4lw)}}{8}
\\ = \frac{-2(l + w) \pm \sqrt{(4(l^2 + 6lw + w^2)}}{8}$
$= \frac{-2(l + w) \pm 2\sqrt{l^2 + 6lw + w^2}}{8} \\= \frac{2}{8}(-(l + w) \pm \sqrt{l^2 + 6lw + w^2}) \\x = \frac{1}{4}(-(l + w) \pm \sqrt{l^2 + 6lw + w^2}) \\\boxed{x = \frac{1}{4}\left(-(l + w) + \sqrt{l^2 + 6lw + w^2} \right) \text{ or }}
\\\boxed{x = -\frac{1}{4}\left((l + w) + \sqrt{l^2 + 6lw + w^2} \right)}$

Since $(l + w) + \sqrt{l^2 + 6lw + w^2} \ \textgreater \ 0$ , $-\frac{1}{4}\left((l + w) + \sqrt{l^2 + 6lw + w^2}\right)$ is negative. Since x represents the patio width, x cannot be negative. Hence, the patio width is given by

$\boxed{x = \frac{1}{4}\left(-(l + w) + \sqrt{l^2 + 6lw + w^2} \right)}$

7 0

3 years ago