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sergiy2304 [10]
2 years ago
15

A line passes through the point -10,9 and has a slope of 1/2. Write an equation in slope-intercept form for this line

Mathematics
1 answer:
vitfil [10]2 years ago
7 0

Answer:

Step-by-step explanation:

The slope intercept form of an equation of a line is y = mx + b, where m is the slope and b is the y-intercept (the value of y when x=0).

Since the slope is (1/2), we can write:

y = (1/2)x + b

We want a value of b such that it forces the line to go through point (-10,9).  Enter that point in the equation and solve for b:

y = (1/2)x + b

9 = (1/2)*(-10) + b

9 = -5 + b

b = 14

The eqyuation of a line with a slope of (1/2) and goes through point (-10,9) is:

y = (1/2)x + 14

See attachment.

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