Apply the product rule to
7
11
7
11
.
(
2
7
)
2
⋅
7
2
11
2
(
2
7
)
2
⋅
7
2
11
2
Raise
7
7
to the power of
2
2
.
(
2
7
)
2
⋅
49
11
2
(
2
7
)
2
⋅
49
11
2
Raise
11
11
to the power of
2
2
.
(
2
7
)
2
⋅
49
121
(
2
7
)
2
⋅
49
121
Multiply
2
(
49
121
)
2
(
49
121
)
.
Tap for more steps...
(
2
7
)
98
121
(
2
7
)
98
121
Apply the product rule to
2
7
2
7
.
2
98
121
7
98
121
2
98
121
7
98
121
The result can be shown in multiple forms.
Exact Form:
2
98
121
7
98
121
2
98
121
7
98
121
Decimal Form:
0.36253492
…
0.36253492
…
(
2
7
)
2
⋅
(
7
1
1
)
2
(
2
7
)
2
⋅
(
7
1
1
)
2
Answer:
the answer of the question is D
To solve this problem we must find 5% of 1418 and 4% of 1418
which is

so that would be 70.9 house extra in the first year and 56.72 extra in the second year respectively.
so to find the total number of houses we must add 70.9 + 56.72 + 1418 which gives us 1545.62
at the last it is mentioned for us to round our answer to the nearest
they are asking us for the total number whole number
which is 1546
so there would be 1546 houses in the second year.
If the length of the wall is 18 feet, then the wall on the plan is 3.6 inches long
<u>Solution:</u>
According to Tom, 2.6 inches equals to 13 feet
Length of the wall = 18 feet
If 2.6 inches is equal to 13 feet, then 1 feet is equal to:

So, 1 feet = 0.2 inches …….(1)
Now, we have to determine the length of the wall on the plan which is 18 feet long
Using Equation (1), 18 feet = 18 × 0.2 inches = 3.6 inches
Hence , the wall on the plan is 3.6 inches long
Answer:
10 1/2 pounds are needed.
Step-by-step explanation:
7 x 1.5 = 10.5