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Andrew [12]
3 years ago
15

Mitch is buying candy bars for his friends he wants to give to 2 bars to each friend he wants to be to have 10 spare bars you ca

n afford to buy 24 Candy bar.What is the algebraic sentence that will help him figure out how many friends he can treat? Let F= the number of friends
Mathematics
2 answers:
Bad White [126]3 years ago
8 0

Answer:Mitch can gift 7 friends giving each friend 2 each

Step-by-step explanation:

Lelu [443]3 years ago
6 0

Answer:

13 friends

Step-by-step explanation:

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Given f(x)=17x-18, find x when f(x)=33
vichka [17]
33=17x-18 add 18 both sides
51=17x. divide 17 both sides
3 = x
3 0
3 years ago
So what is the answer to The spinner below is spun twice. What is the probability of the arrow landing on a 3 and then on an odd
babymother [125]

Answer: nijja what

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
If tanA+sinA=m and tanA-sinA=n.prove that m^2-n^2=4√mn
mash [69]

Let a=\tan A and b=\sin A. Then

m^2-n^2=(a+b)^2-(a-b)^2=(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab

\implies m^2-n^2=4\tan A\sin A

and

mn=(a+b)(a-b)=a^2-b^2

\implies4\sqrt{mn}=4\sqrt{\tan^2A-\sin^2A}

The expression under the square root can be rewritten as

\tan^2A-\sin^2A=\dfrac{\sin^2A}{\cos^2A}-\sin^2A=\sin^2A\left(\dfrac1{\cos^2A}-1\right)=\sin^2A(\sec^2A-1)

Recall that

\sin^2A+\cos^2A=1\implies\tan^2A+1=\sec^2A

so that

\tan^2A-\sin^2A=\sin^2A\tan^2A

and assuming \sin A>0 and \tan A>0, we end up with

4\sqrt{\tan^2A-\sin^2A}=4\tan A\sin A

so that

m^2-n^2=4\sqrt{mn}

as required.

5 0
3 years ago
Jake is going to call one person from his contacts at random. He has 30 total contacts. 16 of those contacts are people he met a
Archy [21]
Answer: P = 8/15

Explanation:

There are 30 contact in total

And there are 16 contacts are people he met at school

P = 16/30 = 8/15
4 0
3 years ago
Read 2 more answers
PLEASE I REALLY NEED HELP!
vagabundo [1.1K]

Answer:

\frac{3}{28}

Step-by-step explanation:

Probability (P) is calculated as

P = \frac{requiredoutcome}{count}

The first required outcome is a red sweet from a total of 3 + 5 = 8

P( red) = \frac{3}{8}

There are now 2 red left and a count of 7, since 1 has been eaten, thus

P( second red ) = \frac{2}{7}

P( red and red ) = \frac{3}{8}  × \frac{2}{7} = \frac{6}{56} = \frac{3}{28}

6 0
3 years ago
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