Luis could make 0, 1, 2 or 3 touchdowns. We know that in the past he
made 0 touchdowns 4 times, 1 touchdown 7 times, 2 touchdowns 9 times and 3 touchdowns 6 times. To make a probability distribution table, add up 4, 7, 9 and 6; the sum is 26. Thus, based upon past experience, the probability of his making 0 touchdowns is 4/26, of 1 touchdown 7/26, of 2 touchdowns, 9/26 and of 3 touchdowns 6/26: {0.154, 0.269, 0.346, 0.231}. Important: Note that these four decimal probabilities add up to 1, as they must.
The empirical probability of Luis' scoring 2 touchdowns is 0.346.
To find the probability of his scoring more than 1 touchdown, add together the probabilities of his scoring 2 and 3 touchdowns: 0.346+0.231 = 0.577.
The expected value can be calculated as follows:
0(0.154) + 1(0.269) + 2(0.346) + 3(0.231). Note that each term in this expression comes from {0, 1, 2, 3}, and that the fractions all represent the probabilities of each of these four possible outcomes.
The sum is 1.65. This is the "expected value" of the number of touchdowns Luis will likely make. 1.65 is obviously more than 0 or 1 touchdowns, but less than 3 or 4 touchdowns.
Answer is
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Answer:
a + b = 5.30
a + b = 7
No
Step-by-step explanation:
Expressing the information as system of linear equation :
Let apples = a, oranges = b
If $5.30 is charged for one apple and one orange, then we have ;
a + b = 5.30 - - - (1)
If $14 is charged for 2 apples and 2 oranges, then we have ;
2a + 2b = 14 - - - - (2)
a + b = 7
Since both equations gives varying combined cost for equal amount of the fruit, then a unique cost cannot be obtained for each fruit from the systems of equation using simultaneous equation process.
From (1)
a = 5.30 - b
Put a = 5.30 - b in (2)
2(5.30 - b) + 2b = 14
10.6 - 2b + 2b = 14
10.6 = 14 - - - - - (variables cancels out).
Answer: The predicted difference in sleep is 1251437 minutes.
Step-by-step explanation:
Since we have given that
Number of years of education = 12 years
Number of minutes a week = 2000
As we have
In case of individual A:
7 days = 2000 minutes
1 year = 365 days = 
12 years = 
In case of individual B:
7 days = 3000 minutes
1 year = 365 days = 
16 years = 
minutes
So, the predicted difference in sleep between individuals A and B is given by
Hence, the predicted difference in sleep is 1251437 minutes.
