3141.6 cubic meters
Step-by-step explanation:
The volume of a cylinder is given by;
πr²h
π * (²⁰/₂)² * 10
π * 100 * 10
= 3141.6
Answer:
x =-1
y =-1
Step-by-step explanation:
to solve this system of equation, using substiution method
3x-4y=1 ........................ equation 1
x=2y+1 ............................ equation 2
subbstitute for x into equation 1
3x-4y=1 ........................ equation 1
3(2y + 1) - 4y = 1
6y + 3 -4y = 1
2y + 3 = 1
collect the like terms
2y = 1- 3
2y= -2
divide both sides by the coefficient of y which is y
2y/2 = -2/2
y = -1
put the value of y =-1 into equation 2
x=2y+1 ............................ equation 2
x = 2(-1) + 1
x = -2 + 1
x = -1
therefore x =-1 y = -1
Answer:
Option (C)
Option (C)
Option (A)
Step-by-step explanation:
Part A.
Frank's walking speed can be represented by the equation.
Equation representing the speed is,
y = 85x
Therefore, walking speed of Frank = 85 meters per minute.
Option (C) will be the answer.
Part B.
Distance walked over the time by Jeffrey is given by the graph attached.
Equation for the speed will be,
y = 
y = 80x
Therefore, walking speed of Jeffrey = 80 meters per minute
Difference in the speed of Frank and Jeffrey = 85 - 80 = 5 meters per minute.
Jeffery walks 5 meters per minute slower than Frank.
Option (C) will be the answer.
Part (C)
Distance traveled by Frank in 16 minutes,
y = 85(16) = 1360 meters
Time taken to travel the same distance by Jeffrey will be,
1360 = 80x
x = 
meters per minute
Option (A) will be the answer.
Recall that a ⇒ b ≡ ¬a ∨ b.
• r ⇒ (p ∧ q) ≡ ¬r ∨ (p ∧ q)
In row C, q is false so p ∧ q false, and r is true so ¬r is false.
¬r ∨ (p ∧ q) ≡ false ∨ false ≡ false
• r ⇒ (p ∨ q) ≡ ¬r ∨ (p ∨ q) = p ∨ q ∨ ¬r
In each of rows A, C, and E, at least one of p or q is true, so
p ∨ q ∨ ¬r = true
• (q ∧ r) ⇒ p ≡ ¬(q ∧ r) ∨ p ≡ (¬q ∨ ¬ r) ∨ p = p ∨ ¬q ∨ ¬r
In row E, p is false and both q and r are true, so ¬q and ¬r are both false.
false ∨ false ∨ false = false
• (q ∨ r) ⇒ p ≡ ¬(q ∨ r) ∨ p ≡ (¬q ∧ ¬r) ∨ p
In row E, p is false and both q and r are true, so both ¬q and ¬r are false.
(¬q ∧ ¬r) ∨ p ≡ (false ∧ false) ∨ false ≡ false ∨ false ≡ false
