Answer:
x = √30
Step-by-step explanation:
From small triangle BDC:
using Pythagorean theorem
CB² = BD² + DC²
x² = BD² + 3²
Fron triangles BDC and ADB.
ΔBDC has long leg BD and short leg DC.
ΔADB has long leg AD and shirt leg BD.
AD : BD = BD : DC
7 : BD = BD : 3
7*3 = BD*BD
BD² = 7*3 = 21
x² = BD² + 3² = 21+9 = 30
x² = 30
x = √30
Answer:
Step-by-step explanation:
We have the polynomial
( 1 )
To solve this problem we have to take into account that only we can sum term with the same order in the variable. We have the polynomials
we can note (by summing term by term) that only the sum of the first and the fourth equation correspond to the given polynomial ( 1 ) of the problem. If we organize these polynomials (that is, write the equation down in a form where higher order appears first ) we have
and if we sum we obtain
that is what we was looking for
I hope this is useful for you
regards
This is equivalent to an 11x15 rectangle with 2 circles each of radius 2cm cut out of it (4 semi-circles = 2 circles in area).
11x11 rectangle = 165cm^2 area.
2 circles of 2cm radius = 2*4pi = 8pi = 25.13
165 - 25.13 = 139.87 139.9 (A)
Answer:
Your answer should be the Second one 3x + 4 - x = 3x + 4
Step-by-step explanation:
Hope this helps :) Have a great day!