Monthly amount, M = $102×4 = $408.
Also, yearly amount, Y = M×12 = $408×12 = $4896
It is given that 25% of the cost is contributed by Marcus.
Amount Marcus paid
Therefore, his employer contribution annually for coverage is $( 4896 - 1224)=$3672.
Hence, this is the required solution.
The solution of the system of equations is (-3 , -2)
Step-by-step explanation:
Steps for Using Linear Combinations Method)
- Arrange the equations with like terms in columns
- Analyze the coefficients of x or y
- Add the equations and solve for the remaining variable
- Substitute the value into either equation and solve
∵ 3 x - 8 y = 7 ⇒ (1)
∵ x + 2 y = -7 ⇒ (2)
- Multiply equation (2) by 4 to make the coefficients of y are equal in
magnitude and different in sign
∴ 4 x + 8 y = -28 ⇒ (3)
Add equations (1) and (3)
∵ 3 x - 8 y = 7 ⇒ (1)
∵ 4 x + 8 y = -28 ⇒ (3)
∴ 7 x = -21
- Divide both sides by 7
∴ x = -3
Substitute the value of x in equation (2) to find y
∵ x + 2 y = -7 ⇒ (2)
∵ x = -3
∴ -3 + 2 y = -7
- Add 3 to both sides
∴ 2 y = -4
- Divide both sides by 2
∴ y = -2
The solution of the system of equations is (-3 , -2)
Learn more:
You can learn more about the system of the linear equations in brainly.com/question/13168205
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Stop asking questons we are pretty much telling you the answer figure it out your self
so the investigator found the skid marks were 75 feet long hmmm what speed will that be?
![s=\sqrt{30fd}~~ \begin{cases} f=\stackrel{friction}{factor}\\ d=\stackrel{skid}{feet}\\[-0.5em] \hrulefill\\ f=\stackrel{dry~day}{0.7}\\ d=75 \end{cases}\implies s=\sqrt{30(0.7)(75)}\implies s\approx 39.69~\frac{m}{h}](https://tex.z-dn.net/?f=s%3D%5Csqrt%7B30fd%7D~~%20%5Cbegin%7Bcases%7D%20f%3D%5Cstackrel%7Bfriction%7D%7Bfactor%7D%5C%5C%20d%3D%5Cstackrel%7Bskid%7D%7Bfeet%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20f%3D%5Cstackrel%7Bdry~day%7D%7B0.7%7D%5C%5C%20d%3D75%20%5Cend%7Bcases%7D%5Cimplies%20s%3D%5Csqrt%7B30%280.7%29%2875%29%7D%5Cimplies%20s%5Capprox%2039.69~%5Cfrac%7Bm%7D%7Bh%7D)
nope, the analysis shows that Charlie was going faster than 35 m/h.
now, assuming Charlie was indeed going at 35 m/h, then his skid marks would have been
![s=\sqrt{30fd}~~ \begin{cases} f=\stackrel{friction}{factor}\\ d=\stackrel{skid}{feet}\\[-0.5em] \hrulefill\\ f=\stackrel{dry~day}{0.7}\\ s=35 \end{cases}\implies 35=\sqrt{30(0.7)d} \\\\\\ 35^2=30(0.7)d\implies \cfrac{35^2}{30(0.7)}=d\implies 58~ft\approx d](https://tex.z-dn.net/?f=s%3D%5Csqrt%7B30fd%7D~~%20%5Cbegin%7Bcases%7D%20f%3D%5Cstackrel%7Bfriction%7D%7Bfactor%7D%5C%5C%20d%3D%5Cstackrel%7Bskid%7D%7Bfeet%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20f%3D%5Cstackrel%7Bdry~day%7D%7B0.7%7D%5C%5C%20s%3D35%20%5Cend%7Bcases%7D%5Cimplies%2035%3D%5Csqrt%7B30%280.7%29d%7D%20%5C%5C%5C%5C%5C%5C%2035%5E2%3D30%280.7%29d%5Cimplies%20%5Ccfrac%7B35%5E2%7D%7B30%280.7%29%7D%3Dd%5Cimplies%2058~ft%5Capprox%20d)
Answer:
x = -1
Step-by-step explanation:
5 + 2x + 6 = x + 10
11 + 2x = x + 10
-x -x
11 + x = 10
-11 -11
x= -1
