Hello there,
Well to find the total time you would have to set up a proportion...
6 / 3/5 = x / 1
Now you crosss multiply and divide...
6 * 1 = 6
6 / 3/5 =30/3 = 10
Answer: 10 hours
Hope I helped!!
-Char
Answer:
sin(A-B) = 24/25
Step-by-step explanation:
The trig identity for the differnce of angles tells you ...
sin(A -B) = sin(A)cos(B) -sin(B)cos(A)
We are given that sin(A) = 4/5 in quadrant II, so cos(A) = -√(1-(4/5)^2) = -3/5.
And we are given that cos(B) = 3/5 in quadrant I, so sin(B) = 4/5.
Then ...
sin(A-B) = (4/5)(3/5) -(4/5)(-3/5) = 12/25 + 12/25 = 24/25
The desired sine is 24/25.
3 weeks x 110 minutes = 330 minutes
330 minutes a week x 14 weeks = 4620 minutes
4620 divided by 60 minutes = 77 hours
77 hours is your answer
You need the Law of Cosines here and you use it when you have 2 sides and an enclosed angle. The side across from the angle is the one we are looking for. The correct way to express the Law using what we have is the last choice above. Side RT is the unknown, and it is across from the angle that is enclosed between the 2 other sides.
