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Ronch [10]
3 years ago
5

The sum of 3 consecutive odd integers is 19 more than twice the smallest of integers , what are the integers ?

Mathematics
1 answer:
Sedaia [141]3 years ago
6 0

Answer:

13, 15, 17

Step-by-step explanation:

If we let the smallest of these odd integers be "x"

then the next one is "x + 2"

and next one is "x + 4"

We can write an equation from the word problem:

x + x+2 + x + 4 = 2x + 19

let's find x, the smallest, and then find the other 2:

x + x+2 + x + 4 = 2x + 19\\3x+6=2x+19\\x=19-6\\x=13

The next one is 15, and next one is 17

The three consecutive odd integers are 13, 15, 17

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Step-by-step explanation:

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Let A be the event that the sum of outcomes is 7

A = \{(1,6), (2,5), (3,4) , (4,3) , (5,2), (6,1)\}

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The probability for rolling a sum of 7 is: 1/6

Keywords: Probability, sample space

Learn more about probability at:

  • brainly.com/question/1446555
  • brainly.com/question/1446243

#LearnwithBrainly

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