The sum of 3 consecutive odd integers is 19 more than twice the smallest of integers , what are the integers ?
1 answer:
Answer:
13, 15, 17
Step-by-step explanation:
If we let the smallest of these odd integers be "x"
then the next one is "x + 2"
and next one is "x + 4"
We can write an equation from the word problem:
x + x+2 + x + 4 = 2x + 19
let's find x, the smallest, and then find the other 2:
The next one is 15, and next one is 17
The three consecutive odd integers are 13, 15, 17
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The probability for rolling a sum of 7 is: 1/6
Step-by-step explanation:
Given that two six-sided dies are rolled the total outcomes will be:
n(S) = 36
Out of total outcomes we have to count the outcomes that sum up to 7
Let A be the event that the sum of outcomes is 7
Here the first number is the result of first die and second number is the result of 2nd die.
n(A) = 6
So the probability of A will be:
Hence,
The probability for rolling a sum of 7 is: 1/6
Keywords: Probability, sample space
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