Question

The sum of 3 consecutive odd integers is 19 more than twice the smallest of integers , what are the integers ?

Answer 1

Answer:

13, 15, 17

Step-by-step explanation:

If we let the smallest of these odd integers be "x"

then the next one is "x + 2"

and next one is "x + 4"

We can write an equation from the word problem:

x + x+2 + x + 4 = 2x + 19

let's find x, the smallest, and then find the other 2:

$x + x+2 + x + 4 = 2x + 19\\3x+6=2x+19\\x=19-6\\x=13$

The next one is 15, and next one is 17

The three consecutive odd integers are 13, 15, 17