Answer:
you cant figure that out.
Step-by-step explanation:
Answer:
Therefore the length of QP = 3.4 units
Step-by-step explanation:
Given:
PQ = 2x + 1
XF = 7x - 4
PF = x
Q is the mid poimt of XF
∴ XQ = QF
QF = PQ - PF ..........( Q - F - P )
= 2x + 1 - x
∴ QF = x + 1
∴ XQ = QF = x + 1
TO Find:
QP = ?
Solution:
By Addition Property we have
![XP = XQ + QF+PF ..........(X-Q-F-P)\\\\](https://tex.z-dn.net/?f=XP%20%3D%20XQ%20%2B%20QF%2BPF%20..........%28X-Q-F-P%29%5C%5C%5C%5C)
![XF + PF =XQ + QF+PF ..........(X-Q-F-P)\\](https://tex.z-dn.net/?f=XF%20%2B%20PF%20%3DXQ%20%2B%20QF%2BPF%20..........%28X-Q-F-P%29%5C%5C)
Substituting the given values in above equation we get
(7x - 4) + x = (x +1) + (x +1) + x
8x -4 = 3x +2
8x - 3x + 4 + 2
5x = 6
∴ ![x = \frac{6}{5}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B6%7D%7B5%7D)
Now we require
QP = (2x + 1)
∴ ![QP = 2\times \frac{6}{5} +1\\\\QP = \frac{12+5}{5} \\\\QP =\frac{17}{5} \\\\\therefore QP = 3.4\ unit](https://tex.z-dn.net/?f=QP%20%3D%202%5Ctimes%20%5Cfrac%7B6%7D%7B5%7D%20%2B1%5C%5C%5C%5CQP%20%3D%20%5Cfrac%7B12%2B5%7D%7B5%7D%20%5C%5C%5C%5CQP%20%3D%5Cfrac%7B17%7D%7B5%7D%20%5C%5C%5C%5C%5Ctherefore%20QP%20%3D%203.4%5C%20unit)
Therefore the length of QP = 3.4 units
Answer:
97.5 m^2
Step-by-step explanation:
Given data
Length = 65m
Width= 30m
We are told that the width of the path= 1.5m
Hence the area of the path is
=65*1.5
=97.5 m^2
I can’t remember the answer but I learned that a while back