Answer:
i think that the answer might be D
Answer: f(3)=-20
Step-by-step explanation:
If you look at f(x) and f(3), you can see that 3 is in place of x. That means when x=3, what is f(x). You plug in x=3 into f(x) and solve.
f(3)=-2(3)²-2
f(3)=-2(9)-2
f(3)=-18-2
f(3)=-20
Answer:
The answer to your question is z = ![\sqrt{24}](https://tex.z-dn.net/?f=%5Csqrt%7B24%7D)
Step-by-step explanation:
Process
I'll solve this problem using proportions, I hope it helps you
We consider the adjacent side of both triangle
Adjacent side small triangle = x Adjacent side big triangle = 10
Proportion of these sides = ![\frac{x}{10}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B10%7D)
Now, consider the opposite side of both triangles
Opposite side fo small triangle = 2 Opposite side big triangle = x
Proportion = ![\frac{2}{x}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7Bx%7D)
Now, equal both proportions and solve for x
![\frac{x}{10} = \frac{2}{x}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B10%7D%20%3D%20%5Cfrac%7B2%7D%7Bx%7D)
x² = 20
x = ![\sqrt{20}](https://tex.z-dn.net/?f=%5Csqrt%7B20%7D)
x = 2
Using Geometric mean
x = ![\sqrt{2x10} = \sqrt{20}](https://tex.z-dn.net/?f=%5Csqrt%7B2x10%7D%20%3D%20%5Csqrt%7B20%7D)
Using the Pythagorean theorem to find z
z² = (√20)² + 2²
z² = 20 + 4
z² = 24
z = ![\sqrt{24}](https://tex.z-dn.net/?f=%5Csqrt%7B24%7D)
Answer:
or ![Probability = 0.2](https://tex.z-dn.net/?f=Probability%20%3D%200.2)
Step-by-step explanation:
Given
![Black = 25](https://tex.z-dn.net/?f=Black%20%3D%2025)
![White = 35](https://tex.z-dn.net/?f=White%20%3D%2035)
![Red = 40](https://tex.z-dn.net/?f=Red%20%3D%2040)
Required
Determine the probability of selecting Black and Red
First, we need to calculate the number of red and black balls
The probability is calculated as thus:
![Probability = P(Black\ and \ Red) \ or\ P(Red\ and \ Black)](https://tex.z-dn.net/?f=Probability%20%3D%20P%28Black%5C%20and%20%5C%20Red%29%20%5C%20or%5C%20P%28Red%5C%20and%20%5C%20Black%29)
Convert to mathematical expressions
![Probability = [P(Black) *P(Red)] + [P(Red) *P(Black)]](https://tex.z-dn.net/?f=Probability%20%3D%20%5BP%28Black%29%20%2AP%28Red%29%5D%20%2B%20%5BP%28Red%29%20%2AP%28Black%29%5D)
Solve for each probaility;
![P(Black) = \frac{Black}{Total} = \frac{25}{100}](https://tex.z-dn.net/?f=P%28Black%29%20%3D%20%5Cfrac%7BBlack%7D%7BTotal%7D%20%3D%20%5Cfrac%7B25%7D%7B100%7D)
![P(Red) = \frac{Red}{Total} = \frac{40}{100}](https://tex.z-dn.net/?f=P%28Red%29%20%3D%20%5Cfrac%7BRed%7D%7BTotal%7D%20%3D%20%5Cfrac%7B40%7D%7B100%7D)
So, we have:
![Probability = [P(Black) *P(Red)] + [P(Red) *P(Black)]](https://tex.z-dn.net/?f=Probability%20%3D%20%5BP%28Black%29%20%2AP%28Red%29%5D%20%2B%20%5BP%28Red%29%20%2AP%28Black%29%5D)
![Probability = [\frac{25}{100} *\frac{40}{100}] + [\frac{40}{100} *\frac{25}{100}]](https://tex.z-dn.net/?f=Probability%20%3D%20%5B%5Cfrac%7B25%7D%7B100%7D%20%2A%5Cfrac%7B40%7D%7B100%7D%5D%20%2B%20%5B%5Cfrac%7B40%7D%7B100%7D%20%2A%5Cfrac%7B25%7D%7B100%7D%5D)
![Probability = [\frac{1000}{10000}] + [\frac{1000}{10000}]](https://tex.z-dn.net/?f=Probability%20%3D%20%5B%5Cfrac%7B1000%7D%7B10000%7D%5D%20%2B%20%5B%5Cfrac%7B1000%7D%7B10000%7D%5D)
![Probability = [\frac{1}{10}] + [\frac{1}{10}]](https://tex.z-dn.net/?f=Probability%20%3D%20%5B%5Cfrac%7B1%7D%7B10%7D%5D%20%2B%20%5B%5Cfrac%7B1%7D%7B10%7D%5D)
![Probability = \frac{1+1}{10}](https://tex.z-dn.net/?f=Probability%20%3D%20%5Cfrac%7B1%2B1%7D%7B10%7D)
![Probability = \frac{2}{10}](https://tex.z-dn.net/?f=Probability%20%3D%20%5Cfrac%7B2%7D%7B10%7D)
![Probability = \frac{1}{5}](https://tex.z-dn.net/?f=Probability%20%3D%20%5Cfrac%7B1%7D%7B5%7D)
or
![Probability = 0.2](https://tex.z-dn.net/?f=Probability%20%3D%200.2)