Could it be A 116 and B 32 try that.
Given:
A circle with diameter 9 cm.
To find:
The area of the circle.
Solution:
The area of a circle is:
...(i)
Where r is the radius.
We know that, the diameter of a circle is twice than its radius.
The diameter of the given circle is 9 cm.
Substituting 
in (i), we get
Therefore, the area of the given circle is 63.6.
Answer:
when two inscribed angles in one circle both equal 75°, the two angles must intercept the same arc that measures 75°.
Step-by-step Explanation:
The relationship between an intercepted arc and an inscribed angle is given as:
the measure of the intercepted arc = twice the inscribed angle that intercepts it.
Also, by virtue of this, when two inscribed angles intercepts the same arc, both inscribed angles are said to be congruent. And the measure of both angles equal the measure of the arc they both intercept.
Therefore, if the measure of an arc, that is intercepted by 2 inscribed angles, is given as 75°, both inscribed angles equal 75° as well. Thus, each of the inscribed angles is half the measure of the intercepted arc.
Therefore, the statement that is true about inscribed angles is: "when two inscribed angles in one circle both equal 75°, the two angles must intercept the same arc that measures 75°."
The upper quartile for NFC is 3 points higher than that of AFC.
<h3>What is the difference in the upper quartiles?</h3>
A box plot is used to study the distribution and level of a set of scores. The scores are distributed into 4 groups. Each group has a value of 25%
On the box, the third line on the box represents the upper quartile. 75% of the scores represents the upper quartile.
Upper quartile for AFC : 26
Upper quartile for NFC : 23
Difference = 26 - 23 = 3
To learn more about box plots, please check: brainly.com/question/27215146
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