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2 years ago

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Problem 17 Mrs. Casey, a sixth grade math teacher, ordered one package of pencils for each of her 92 students Each package conta

ined a dozen pencils. How many pencils did Mrs. Casey order?

1 answer:

Semmy [17]2 years ago

4 0

Answer:

1104

Step-by-step explanation:

1 package had 12 pencils

thus, 92 packages will have = (92*12) = 1104 pencils

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Please help me answer.

katen-ka-za [31]

Answer:

Slope-intercept: y=3/4x+1

Sorry idk how to do general form

Step-by-step explanation:

Slope-intercept form is y=mx+b, m being the slope, b being the y-intercept.

The slope of this graph is 3/4, and the y-intercept is 1.

4 0

3 years ago

Read 2 more answers

4 Tan A/1-Tan^4=Tan2A + Sin2A

Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0

2 years ago

Right two equal fractions 2/3

saveliy_v [14]

Two equal fractions would be 4/6 and 6/9.

8 0

2 years ago

Right or wrong ????

tangare [24]

Answer:

c 1/2

Step-by-step explanation:

You are incorrect.

We are going from ABCDEFGH to A'B'C'D'E'F'G'H'. We are going from the large octagon to the small octagon. The scale factor of a dilation is the number you multiply the original lengths to get the lengths of the dilation.

$scale~factor = \dfrac{length~of~dimension~in~dilated~image}{length~of~corresponding~dimension~in~original~figure}$

Look at point (6, 0) which becomes (3, 0) in the dilation.

The distance from the origin to (6, 0) is 6 units.

The distance from the origin to (3, 0) is 3 units.

scale factor = dilated/original = 3/6 = 1/2

The scale factor of the dilation is 1/2.

Also look at segment AB whose length is 4. The length of segment A'B' is 2.

scale factor = dilated/original = 2/4 = 1/2

Answer: 1/2

4 0

3 years ago

All natural numbers are real numbers

docker41 [41]

Answer: True

Step-by-step explanation: Natural numbers are the set of counting numbers and they begin at 1 and go on forever. All natural numbers are real numbers. In fact, the majority of numbers are real numbers such as imaginary numbers.

6 0

2 years ago