Let's simplify step-by-step.<span><span>5<span>(<span><span>4x</span>+3</span>)</span></span>+<span>5<span>(<span>9−x</span>)</span></span></span>Distribute:<span>=<span><span><span><span><span>(5)</span><span>(<span>4x</span>)</span></span>+<span><span>(5)</span><span>(3)</span></span></span>+<span><span>(5)</span><span>(9)</span></span></span>+<span><span>(5)</span><span>(<span>−x</span>)</span></span></span></span><span>=<span><span><span><span><span>20x</span>+15</span>+45</span>+</span>−<span>5x</span></span></span>Combine Like Terms:<span>=<span><span><span><span>20x</span>+15</span>+45</span>+<span>−<span>5x</span></span></span></span><span>=<span><span>(<span><span>20x</span>+<span>−<span>5x</span></span></span>)</span>+<span>(<span>15+45</span>)</span></span></span><span>=<span><span>15x</span>+<span>60
Answer is B</span></span></span>
Answer:
uhm is it.... 8????
Step-by-step explanation:
Answer:
54%
Step-by-step explanation:
Given : A coin is tossed two times successively.
Solution:
Formula used: Probability = ![\frac{\text{number of outcome}}{\text{total number of outcome}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bnumber%20of%20outcome%7D%7D%7B%5Ctext%7Btotal%20number%20of%20outcome%7D%7D)
(i) Sample space
![HH\\HT\\TH\\TT\\](https://tex.z-dn.net/?f=HH%5C%5CHT%5C%5CTH%5C%5CTT%5C%5C)
(ii) P( getting exactly one head) = ![\frac{2}{4}= \frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B4%7D%3D%20%5Cfrac%7B1%7D%7B2%7D)
(iii) P( getting no heads)=![\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D)
(iv)P( getting at least one tail)=![\frac{3}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D)
It's closer to 4.97 because if you round to the nearest tenths, you will get 4.97.