I'm not sure about part B, but part A will have the answer "if Ron eats lunch today, then he will drink a glass of milk" (without quotes of course)
The idea is that we have these arguments in symbolic form
P = Ron eats lunch today
Q = Ron eats a sandwich
R = Ron will drink a glass of milk
The format is
"If P then Q" ----> "if Q then R" so therefore "If P then R"
We see that P leads to Q, then Q leads to R. So overall P leads to R. We connect them as a chain of sorts. We can skip over Q since we know the first point will lead to the last. Think of it as a shortcut of sorts.
I believe that it would actually be when it would be a "<span>codominace" as when both of the rabbits would be have a part in this baby.</span>
A...............................................................
3 | x+12 |=6
Start by distributing 3 to both x and 12
You get 3x+36=6
Subtract 36 from both sides
You then get 3x=-30
Divide 3 from both sides getting
x= -10