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2 years ago

Jack ate 3 chocolate squares after school. Each chocolate square had a mass of 8 grams.

2 answers:

5 0

Jack ate 24 grams in total.

You can get this answer my multiplying 8x3 because he ate three pieces and each of the three had eight grams.

Lunna [17]2 years ago

4 0

Answer:

24 grams

Step-by-step explanation:

Since there are three of them, I multiply by the mass, which is 8, and get 24 grams. Hope this helps!

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PLEASE HELP!!!!!!!

andre [41]

Answer:

$\frac{4^{21}}{5^6}$

Step-by-step explanation:

$\left(\frac{4^7}{5^2}\right)^3$

$=\frac{\left(4^7\right)^3}{\left(5^2\right)^3}$

$\left(4^7\right)^3$

$=4^{21}$

$=\frac{4^{21}}{\left(5^2\right)^3}$

$\left(5^2\right)^3$

$5^6$

$=\frac{4^{21}}{5^6}$

6 0

3 years ago

DUE FIVE MINUTES HELPPPPPP!!!!!!!!!!!!!!!!

iris [78.8K]

Answer:

This is late you said it was due 5 min. yet I this was posted 5 hours. No one can help now.

Step-by-step explanation:

7 0

2 years ago

Martha and Howard are running at a constant speed in a marathon. Martha runs at 4.5 mph. Howard’s progress is 5 miles an hour. W

Leno4ka [110]

Answer:

the answer is that Howard runs faster.

Step-by-step explanation:

Because 4.5 is the least and then 5.0 is greater than Martha

6 0

3 years ago

The managers of franks snack shack buys hamburgers in packages of 30 and hamburger buns in packages of 24. He cannot buy part of

Andreas93 [3]

Answer:

He has to buy 4 packages of hamburgers in packages of 30 and 5 packages of hamburgers in packages of 24

Step-by-step explanation:

First we have to calculate the least common multiple (LCM) of 24 and 30

We will calculate the LCM of 24 and 30 by prime factorization method

24 = 2*2*2*3 = $2^{3} * 3^{1}$

30 = 2*3*5 = $2^{1} *3^{1}* 5^{1}$

LCM = $2^{3}* 3^{1}*5^{1}$

LCM = 120

So number of hamburger buns = 120

Therefore, he must buy 120/24 = 5 packages of hamburgers in packages of 24 and he must also buy 120/30 = 4 packages of hamburgers in packages of 30

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3 years ago

What does k equal if <br>485= 1/((k)(5.99x10^-3))

Verizon [17]

$k\ne 0$

$485=\frac{1}{(k)(5.99*10^{-3})}\\\\ \frac{485}{1}= \frac{1}{0.00599k}\\\\ 485*0.00599k=1\\\\ k=\frac{1}{485*0.00599}\\\\k\approx 0.3442$

7 0

3 years ago