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3 years ago

Statement 1: If √12 - √8 = a, then √12 + √8 is equal to 4/a.

Mathematics

1 answer:

Nana76 [90]3 years ago

5 0

Answer:

Statement 1 is true; Statement 2 is false.

Step-by-step explanation:

Statement 1:

√12 - √8 = a

Let's use the given value of √12 + √8 ,that is, 4/ a.

If we multiply both the expressions such that their Left Hand Sides get multiplies together and Right Hand Sides together:

=> (√12- √8)(√12 + √8) = a × 4/a

On the LHS,

identity used:

(a-b)(a+b) = a²-b²

On the RHS:

a gets canceled due to its presence in both the numerator as well as the denominator.

=> 12 - 8 = 4

=> 4 = 4

That's it!

We got LHS = RHS, that approves the existence of the given statement.

___________________

Statement 2:

"a + √b is called the rationalizing factor of c + √d if their product is 1"

That's not entirely right!

The correct statement would be:

" a + √b is called the rationalizing factor of c + √d if their product is a rational number ."

Since, rationalizing has got nothing to do with 1, (1 is just another rational number), even if we get 2 by their multiplication, it will be called rationalizing as long as we're getting a rational number.

___________________

Answer:

Hence, I'd say:

Statement 1 is correct but Statement 2 isn't.

That's the third option.

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Solution:

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Now, take the equation

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On solving the brackets, we get

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3 years ago

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blsea [12.9K]

Answer:

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For added benefit consider the following equation:

CH_4+O_2-> CO_2+2H_2O

ASK: Is this equation balanced? Quick answer: No

ASK: So how do we know and how do we then balance it?

DO: Count the number of each atom type you have on each side of the equation:

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As you can see everything is balanced except for O To balance O we can simply add a coefficient of 2 in front of O_2 on the left side which would result in 4 O atoms:

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Step-by-step explanation:

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