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IRISSAK [1]
3 years ago
14

Statement 1: If √12 - √8 = a, then √12 + √8 is equal to 4/a.

Mathematics
1 answer:
Nana76 [90]3 years ago
5 0

Answer:

Statement 1 is true; Statement 2 is false.

Step-by-step explanation:

Statement 1:

√12 - √8 = a

Let's use the given value of √12 + √8 ,that is, 4/ a.

If we multiply both the expressions such that their Left Hand Sides get multiplies together and Right Hand Sides together:

=> (√12- √8)(√12 + √8) = a × 4/a

<em>On</em><em> </em><em>the</em><em> </em><em>LHS</em><em>,</em><em> </em>

<em>identity</em><em> </em><em>used</em><em>:</em>

<em>(</em><em>a-b</em><em>)</em><em>(</em><em>a</em><em>+</em><em>b</em><em>)</em><em> </em><em>=</em><em> </em><em>a</em><em>²</em><em>-</em><em>b</em><em>²</em>

<em>On</em><em> </em><em>the</em><em> </em><em>RHS</em><em>:</em>

<em>a</em><em> </em><em>gets</em><em> </em><em>canceled</em><em> </em><em>due</em><em> </em><em>to</em><em> </em><em>its</em><em> </em><em>presence</em><em> </em><em>in</em><em> </em><em>both</em><em> </em><em>the</em><em> </em><em>numerator</em><em> </em><em>as</em><em> </em><em>well</em><em> </em><em>as</em><em> </em><em>the</em><em> </em><em>denominator</em><em>.</em><em> </em>

=> 12 - 8 = 4

=> 4 = 4

That's it!

We got LHS = RHS, that approves the existence of the given statement.

___________________

Statement 2:

<em>"</em><em>a + √b is called the rationalizing factor of c + √d if their product is 1</em><em>"</em>

That's not entirely right!

The correct statement would be:

<em>"</em><em> </em><em>a + √b is called the rationalizing factor of c + √d if their product is </em><em><u>a</u></em><em><u> </u></em><u><em>rational</em><em> </em><em>number</em><em> </em><em>.</em></u><em><u>"</u></em>

Since, rationalizing has got nothing to do with 1, (1 is just another rational number), even if we get 2 by their multiplication, it will be called rationalizing as long as we're getting a rational number.

___________________

Answer:

Hence, I'd say:

Statement 1 is correct but Statement 2 isn't.

That's the third option.

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