Question

Find the equation of a line that is perpendicular to the line y=1/8x+4 and contains the point (-8,0)

Answer 1

answer

y = -8x - 64

finding slope

a perpendicular line has a slope that is the negative reciprocal of the original graph

since the slope of y = $\frac{1}{8} x+4$ is $\frac{1}{8}$, the perpendicular line has a slope of $\frac{-8}{1} =-8$

values

the equation of a line is y = mx + b

with the point (-8, 0), x = -8 and y = 0

we found the slope to be m = -8

plug in values

y = mx + b

0 = -8(-8) + b

0 = 64 + b

b = -64

final equation

plug m and b into y = mx + b to get

y = -8x - 64