Find the equation of a line that is perpendicular to the line y=1/8x+4 and contains the point (-8,0)
1 answer:
answer
y = -8x - 64
finding slope
a perpendicular line has a slope that is the negative reciprocal of the original graph
since the slope of y = is
, the perpendicular line has a slope of
values
the equation of a line is y = mx + b
with the point (-8, 0), x = -8 and y = 0
we found the slope to be m = -8
plug in values
y = mx + b
0 = -8(-8) + b
0 = 64 + b
b = -64
final equation
plug m and b into y = mx + b to get
y = -8x - 64
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Answer:
1056.25π square units
Step-by-step explanation:
A few formulas an definitions which will help us:
(1) , where c is the circumference of a circle and d is its diameter
(2) , where A is the area of a circle with radius r. To put it in terms of d, remember that a circle's diameter is simply twice its radius, or mathematically, (3)
.
We can rearrange equation (1) to put d in terms of π and c, giving us (4) , and we can make a few substitutions in (2) using (3) and (4) to get use the area in terms of the circumference and π:
We can now substitute c for our circumference, 65, to get our answer in terms of π: