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antiseptic1488 [7]
2 years ago
8

I have a picture of my question please answer this Thanks a lot for all your help

Mathematics
2 answers:
Mars2501 [29]2 years ago
6 0

Answer:

12p = 420

Step-by-step explanation:

7nadin3 [17]2 years ago
4 0
12p is 420 hope that helps
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Find two numbers, both smaller than 150, that have a lowest common multiple of 882 and a highest common factor of 21.
GenaCL600 [577]

Answer:

42 and 21

Step-by-step explanation:

Just divide 882  by  21   to get 42  

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The area of the triangle with sides 60 cm,100 cm and 140 cm is of the form 1500 square root x cm².
Ede4ka [16]

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150

Step-by-step explanation:

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What's the surface area of the square pyramid?? <br><br> Please someone answer fast
Eddi Din [679]

Answer:

33

Step-by-step explanation:

The base/square:

3*3 = 9

The sides:

(3*4)/2 = 6

4 sides:

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3 years ago
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Read 2 more answers
According to a survey, the average American person watches TV for 3 hours per week. To test if the amount of TV in New York City
Neporo4naja [7]

Answer:

Test statistic (t-value) of this one-mean hypothesis test is -2.422.

Step-by-step explanation:

We are given that according to a survey, the average American person watches TV for 3 hours per week. She surveys 19 New Yorkers randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 2.5 hours per week, and the sample standard deviation (s) is 0.9 hours.

We have to test if the amount of TV in New York City is less than the national average.

Let Null Hypothesis, H_0 : \mu \leq 3  {means that the amount of TV in New York City is less than the national average}

Alternate Hypothesis, H_1 : \mu > 3   {means that the amount of TV in New York City is more than the national average}

The test statistics that will be used here is One-sample t-test statistics;

        T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean time = 2.5 hours per week

             s = sample standard deviation = 0.09 hours

             n = sample size = 19

So, <u>test statistics</u> = \frac{2.5 - 3}{\frac{0.9}{\sqrt{19} } } ~ t_1_8

                              = -2.422

Therefore, the test statistic (t-value) of this one-mean hypothesis test (with σ unknown) is -2.422.

8 0
3 years ago
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