3x^2 + 4x - 5 = 0
x = [-b ±√(b^2 - 4ac)]/2a
a = 3
b = 4
c = -5
x = [-4 ±√(16 + 60)]/6
x = [-4 ±√76]/6
x = [-4 ±√(2^2 * 19)]/6
x = [-4 ±2√19]/6
x = [-2 ±√19]/3
x = [-2 + √19]/3
x = [-2 + 4.35]/3
x = 2.35/3
x = 0.78 (rounded to the nearest hundredth)
x = [-2 - ±√19]/3
x = [-2 - 4.35]/3
x = -6.35/3
x = -2.12 (rounded to the nearest hundredth)
<span>∴ x = -2.12 , 0.78 (rounded to the nearest hundredth)</span>
Answer:
3x+1/2x
Step-by-step explanation:
When simplifying algebraic expressions, we should first factorise each term fully to find any common factors. First we should factorise the numerator where 3x2-8x-3 factorises to (3x+1)(x-3). Next, we should factorise the denominator where 2x2-6x factorises to 2x(x-3). Now we see that (x-3) is the highest common factor of both the numerator and denominator, hence we can "cancel" the (x-3) term from both the numerator and denominator. Therefore, the expression simplifies fully to (3x+1)/(2x)
For #3, you just have to plug in the numbers for x.
It tells you what to substitute for x in the question. (x = 0, 1, 2, 3, 4, 5, and 6)
For example, let's substitute 0 for x.
6x - x² (the 2 means square the number, or multiply it by itself)
6(0) - (0)²
0 - 0
= 0.
You'll do that to all the numbers (1-6) and fill out the table.
For #4, you have to solve using the distributive property to find out if the equations on both sides are equal.
I'll do the first one for you.
6a - 8 = 2 (3a - 5)
6a - 8 = 6a - 10
They're not equal.
Answer:
29.86 units
Step-by-step explanation:
In the triangle BIS, IT is the bisector of angle BIS,
Let BI = ST = x... (1)
By angle bisector property of a triangle, we have:
Therefore,
BI = ST =6.93
Perimeter of triangle BIS
= BI + IS + ST + BT
= 6.93 + 12 + 6.93 + 4
= 29.86 units
