Answer:
The answer is, "The image will be in Quadrant II"
Step-by-step explanation:
When is comes to rotating something 180, whether it's clock-wise or counter clock-wise it will end in the opposite place.
This is confusing trying PHOTOMATH
Is there a picture that goes with this problem?
Step-by-step explanation:
We have cartisean points. We are trying to find polar points.
We can find r by applying the pythagorean theorem to the x value and y values.

And to find theta, notice how a right triangle is created if we draw the base(the x value) and the height(y value). We also just found our r( hypotenuse) so ignore that. We know the opposite side and the adjacent side originally. so we can use the tangent function.

Remeber since we are trying to find the angle measure, use inverse tan function

Answers For 2,5

So r=sqr root of 29

So the answer is (sqr root of 29,68).
For -3,3


Use the identity

So that means

So our points are
(3 times sqr root of 2, 135)
For 5,-3.5


So our points are (sqr root of 37.25, 35)
For (0,-5.4)

So r=5.4

So our points are (5.4, undefined)
Answer:
Lets denote
1. eggs as x,
2. edamame as y
3. elbow macaroni as z
The problem then is
min TC=2x+5y+3z
subject to

Step-by-step explanation:
First the objective is to minimize total cost subject to some nutritional requirements.
So the total cost function (TC) is the number of servings multiplied for the corresponding costs. Eggs cost 2, edamame 5, and macaroni 3
Next we have to meet the nutritional requirements, the first of the restrictions is the protein restriction. The problem requires that the meal contains at least 40g of carbohydrates (that is why the restriction is
). Then we add how much each meal component adds to the total, eggs add 2g of carbs, edamame 12g, and macaroni 43g.
Same for protein, we need at least 20 grams of protein (
). Eggs add 17g, edamame adds 12g, and macaroni adds 8g.
Finally we don't want more than 50 grams of fat (
). Eggs add 14g, edamame add 6g and macaroni 1g.
Finally, we add the non negativity restrictions-> we cannot buy negative quantities of these goods, but we allow for zero.