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Alisiya [41]
3 years ago
9

Answer this just tell me the color

Mathematics
1 answer:
dem82 [27]3 years ago
6 0

Answer:

yellow

Step-by-step explanation:

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True of false: 0.004 > 0.400​
olya-2409 [2.1K]

Answer:

Step-by-step explanation:false

8 0
3 years ago
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Un atleta corre 8 km en 24 minutos. Si su rapidez no cambia. ¿Cuánto tiempo tardará en correr 32 km? *
const2013 [10]
Yo peunso 75 mins lo que yo peunso
6 0
3 years ago
Determine whether f(x)=-4(x+3)^2-5 has a maximum or a minimum value, then find that value
Leto [7]

Answer:

Yes it has

Step-by-step explanation:

From my perspective.........

f(x) = -4(x + 3)² - 5

f(x) = -4(x + 3)(x + 3) - 5

f(x) = -4(x² + 6x + 9) - 5

f(x) = -4x² - 24x - 36 - 5

f(x) = -4x² - 24x - 41

Dy/dx = -8x - 24

At minimum Dy/dx = 0

-8x - 24 = 0

-8x = 24

x = 24/-8

x = -3

At minimum

y = -4x² - 24x - 41

y = -4(-3)² - 24(-3) - 41

y = -4(9) + 72 - 41

y = -36 + 72 - 41

y = 36 - 41

y = -5

5 0
3 years ago
3(1-2x)=1/4(6x+9) what does x equal? <br> A) x=1/10<br> B) x=7/10<br> C) x=-12/7<br> D)x=-1/5
harina [27]

Answer:

A

Step-by-step explanation:

3(1-2x)=1/4(6x+9)

3-6x=1 1/2x+2 1/4

-2 1/4          -2 1/4

3/4-6x=1 1/2x

    +6x  +6x

3/4=7 1/2x

/7 1/2   /7 1/2

1/10=x

7 0
3 years ago
Read 2 more answers
can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's clients needs a cylind
shutvik [7]

the new radius be to meet the client's need is 4.9 cm .

<u>Step-by-step explanation:</u>

Here we have , can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's clients needs a cylindrical can that has the same volume but is 15 cm tall. We need to find What must the new radius be to meet the client's need . Let's find out:

Let we have two cylinders of volume V_1 , V_2 with parameters as follows :

r_1=6cm\\h_1=10cm\\r_2=?\\h_2=15cm

We know that volume of cylinder is \pi r^2h , According to question volume of both cylinder is equal i.e

⇒ V_1=V_2

⇒ \pi (r_1)^2h_1= \pi (r_2)^2h_2

⇒ (r_1)^2h_1= (r_2)^2h_2

⇒ \frac{(r_1)^2h_1}{h_2}= (r_2)^2

⇒ (r_2) =\sqrt{ \frac{(r_1)^2h_1}{h_2}}                   Putting all values

⇒ (r_2) =\sqrt{ \frac{(6)^2(10)}{15}}

⇒ (r_2) =\sqrt{ \frac{36(10)}{15}}

⇒ (r_2) =\sqrt{ \frac{360}{15}}

⇒ (r_2) =\sqrt{24}

⇒ (r_2) =4.9cm

Therefore , the new radius be to meet the client's need is 4.9 cm .

7 0
3 years ago
Read 2 more answers
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